Re: transformation equations
- From: rbwinn <rbwinn3@xxxxxxxx>
- Date: Mon, 22 Sep 2008 15:16:07 -0700 (PDT)
On Sep 22, 1:36�pm, papa_r...@xxxxxxxxxxx wrote:
On 20 sep, 23:41, rbwinn <rbwi...@xxxxxxxx> wrote:
On Sep 20, 8:01 pm, "Spaceman" <space...@xxxxxxxxxxxxxxxxxxxxxxxxxx>
wrote:
rbwinn wrote:
I don't see where you are coming up with these imaginary numbers. An
imaginary number is defined as the square root of a negative number,
which does not exist because a negative number can only result from
multiplication of a positive number by a negative number.
Robert.
Do you ever need to use such after you have added two negatives
such as maybe
(-1000)+ (-600) ??
Let me ask you this.
Will you never have to use such after adding negatives?
I have not had occasion to use imaginary numbers. �I do not believe in
them, anyway. �Sort of like the length contraction.
Robert B. Winn
So here we have two smart guys that claim to know about math. One
(Winn) does believe in mathematics but not in imaginary numbers. I
would ask him how would he solve this very trivial equation:
x^2 + 4x + 5 = 0
The other guy (Spaceman) says (-1)(-1) = (-1). I would also ask him
how would he solve this very trivial equation:
x^2 + 5x + 4 = 0
An analysis of the results would also be interesting to read from
both.
Miguel Rios- Hide quoted text -
- Show quoted text -
There are no answers to this problem you gave me. The answers to
spaceman's problem are -4,-1.
.
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