Re: transformation equations

Sue... wrote:
On Sep 22, 5:30 pm, "Spaceman" <space...@xxxxxxxxxxxxxxxxxxxxxxxxxx>
wrote:
papa_r...@xxxxxxxxxxx wrote:
On 22 sep, 17:06, "Spaceman" <space...@xxxxxxxxxxxxxxxxxxxxxxxxxx>
wrote:
papa_r...@xxxxxxxxxxx wrote:
The other guy (Spaceman) says (-1)(-1) = (-1). I would also ask
him how would he solve this very trivial equation:

x^2 + 5x + 4 = 0

So you wish to just hand out an equation that does not
even match any reality?
Can you fit that equation to a real life situation?
With your math but of course, but no reality to match such.
The answer would be x = (-4) but no reality can prove such
exists as an answer or even an equation that fits any reality.

But anyone can make silly equations that make the answer
follow certain guidelines.
Try this and it is even more simple than yours..
x^2 = -16.
Solve for x without using imaginary numbers.
Then you will say.. it does not fit any reality.
Oh but it does.
It is how you "remove" a square from a piece of paper
and the -16 is how many cubic inches are "missing".
Or do you think "removing" a 4 by 4 square makes 16 square
inches appear on the paper?

I don't really care how much you want to play with imaginary
bull*** but when it comes to "reality" and physics but you should
start realizing imaginary numbers only bring about imaginary
phsyics and imaginary equations also like yours..
:)

So please explain when in real life would you multiply a positive
number by a negative number ever? (like your 5x) would have to be.
And don't forget, you have to prove the "negative" is not really a
postive in another direction to prove the x is truly negative at
all. :)

--
James M Driscoll Jr
Creator of the Clock Malfunction Theory
Spaceman

So you are saying that the solution is x = -4, which for sure must
be wrong according to your own malfunctioning rules (remember that
you are stating that (-4)(-4) = -16 ?).

Did you read or are you just playing ignorant?
I said using your math method and I asked you to provide a real
situation where such math would match reality.
I see you won't do such.

So how, by using your own rules, you can affirm that the solution
is x = -4?
According to your malfunctioning math, introducing x = -4 in x^2 +
5x + 4 = 0 gives (-4)(-4) + 5(-4) + 4 <> 0.

As I said.
You can not give a real example that your equation actually fits
so I had to use your "silly" 2 negatives makes a postive rule
to fit your silly "non real" equation.

And I see you ignored my equation completely since you can
not do such without using imaginary bull*** math yet I could
using my simple logic of "there are no real negatives".
So please do inform all of where in real life do you multiply a
negative (that is not just a positive in another direction) times a
positive.

Again,
This is a physics group.
Provide the physical relations for your "math" or go back and play
with your imaginary "physics" in the math group.

Unless you think a coil of wire is indistinguishable
from a pair of conductive plates in the "real" world,
then imaginary numbers have real consequences.

A classic example:

http://en.wikipedia.org/wiki/Power_factor
http://en.wikipedia.org/wiki/AC_power

Poor Sue,
Can't see that the whole sillyness of the imaginary unit
is to actually get the negative answer by bypassing the
silly negative times negative stupidity rule.
LOL

Sue,
What does i = when I ask you to give the answer for
the square root of -1.
:)


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