Re: coordinates and equations.
- From: PD <TheDraperFamily@xxxxxxxxx>
- Date: Fri, 28 Nov 2008 08:20:13 -0800 (PST)
On Nov 28, 9:21 am, rbwinn <rbwi...@xxxxxxxx> wrote:
This is a simple way to think of coordinates for some of our
scientific friends. See, there is an x axis and a y axis and a
z axis. So if we have an equation that says
x^2 + y^2 + z^2 - c^2t^2 = 0
where x, y, and z are coordinates, and t is time on a clock in S, the
frame of reference, and c is the speed of light, then if you
substitute numerical values into the equation, what you end up with is
a sphere with a radius of ct with its center at the origin of S.
Now we will do the same thing with another set of coordinates S'.
(x')^2 + (y')^2 + (z')^2 - c^2(n')^2 = 0
where n' is the time on a clock in S'.
That's interesting, Bobby, but if you use t as a variable to denote
what a clock reads, then a more sensible notation is t for the time
read on a clock stationary in S, and t' for the time read on a clock
stationary in S'. If you prefer to use n' for the clock reading in S',
I suppose that's your prerogative. Would you care to use f'' for the
clock reading in S'', and u''' for the clock reading in S'''?
Scientists have told us that
according to scientific experiments, light is traveling at c=300,000
km/sec according to a clock in S'. So what we end up with here is a
sphere with a radius of c(n') with its center at the origin of S'.
I hope this will help some of our scientific friends to understand
how light propagates. I know it is confusing to them because there is
no length contraction in these equations.
Certainly there is. What do you think the relationship between x and
x' is?
Did you think that length contraction would mean light wouldn't
propagate in a sphere with radius c x time?
Maybe it would help to learn what it is that relativity actually says,
Bobby.
.
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