Re: Planet & Satellite Paradox (just for fun!)

On Jan 14, 1:14 pm, "N:dlzc D:aol T:com \(dlzc\)" <dl...@xxxxxxx>
wrote:
Dear TheoreticalPhysics:

"TheoreticalPhysics" <phys...@xxxxxxxxxxxx> wrote in message

news:943fee78-9e29-409e-b39f-3c88ffc087a8@xxxxxxxxxxxxxxxxxxxxxxxxxxxxxx
On Jan 14, 2:59 am, "N:dlzc D:aol T:com \(dlzc\)" <dl...@xxxxxxx>
wrote:



"TheoreticalPhysics" <phys...@xxxxxxxxxxxx> wrote in message

news:79412218-3973-47ae-a64c-b6beb04a9136@xxxxxxxxxxxxxxxxxxxxxxxxxxxxxx

On Jan 7, 7:59 pm, dlzc <dl...@xxxxxxx> wrote:
Spectra will be blue shifted. Satellite (without
compensating for even classical Doppler shift)
orbiting anomalously fast, magnifying apparent
mass. Orbit is elliptical, with planet *not* at one
of the focii, so they would know either the laws
of physics were broken or compensation would
have to be made.

On Jan 12, 3:05 pm, dlzc <dl...@xxxxxxx> wrote:
No, *decreasing* apparent system mass,
because the orbit is slowed.  Kepler should
still apply. Applying the appropriate
coordinate transforms yields in-system
measurments similar to your own (as you
initially required).

Slower or faster? Less mass or more mass?

With or without coordinate transformations? Use
brain or parrot what you don't understand? I can
neither make you read, nor make you understand.

without transforms

Without transforms, without Doppler correction, the apparent mass
of the approaching system would be high (based on orbital
period), and the apparent mass of the departing system would be
low (based on the same observable).

With only classical Doppler correction on both situations, the
apparent mass of the system would be reduced (again based on the
orbtial period).

And clock pulses and moon orbits are both observables, and they'd
both agree.  You only need to invoke the clock if you are too
impatient to wait for the moon to orbit.

David A. Smith

So, observers on either planet would see the opposing planet as having
increased mass, slowed time and reduced length - correct?


.

Relevant Pages

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