Re: Does gravity do work on the freely falling body?
- From: Phil <acceleratedfreefall@xxxxxxxxx>
- Date: Sat, 25 Apr 2009 06:59:20 -0700 (PDT)
On Apr 25, 7:10 am, Tom Roberts <tjroberts...@xxxxxxxxxxxxx> wrote:
Phil wrote:
On the topic of Pound-Rebka, the outcome of the this experiment
DEPENDS upon the source and the detector not accelerating with respect
to one another.
This depends on one's definition of "accelerating". See my description
in another thread of how to compute this -- what matters are the
LOCATIONS and trajectories of source and detector at the events of
emission and detection, the value of the metric at those locations, and
the connection along the light path; all else is irrelevant in the
actual computation (such as the distance some observer measures between
them, or their accelerations [any meaning]).
I've got news for you Tom. Acceleration isn't "a feeling". It is a
concept which relates to the effect of changing motion. The local
inertial frames located at the detector OBSERVE an inertial object at
the source to be accelerating. The differential acceleration HAS
PHYSICAL MEANING regarding change velocity to the freely falling
frames. An object extended from source to detector IS STRAINED,
meaning that differential acceleration HAS PHYSICAL MEANING to the
freely falling frames. The source and detector are _always at rest
wrt to one another_ meaning that the differential readings on their
accelerometers HAVE NO PHYSICAL MEANING to the relative motion of
their rest frames.
I'll leave you to contemplate that. And I will leave you to
contemplate a conceptualization where acceleration meets the
requirements of changing velocity part of the time ... but not all of
the time. ;o)
.
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