Re: How many mathematicians ...


"Uncle Ben" <ben@xxxxxxxxxxx> wrote in message
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On Apr 23, 1:29 pm, "Androcles" <Headmas...@xxxxxxxxxxxxxxxx> wrote:
"Uncle Ben" <b...@xxxxxxxxxxx> wrote in message

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On Apr 23, 11:25 am, "Androcles" <Headmas...@xxxxxxxxxxxxxxxx> wrote:>
"Uncle Ben" <b...@xxxxxxxxxxx> wrote in message

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On Apr 22, 11:39 pm, "Androcles" <Headmas...@xxxxxxxxxxxxxxxx> wrote:
...

1/7 = 0.\142857\ + h

If we multiply both sides by 7, we get
1 = 0.\999999\ + 7h
QED.

...

So,

1 = 0.\99999\ + 7h

and earlier

1 = 0.\99999\ + h

Subtracting,

0 = 6h
============================
h/7 < h and see lemma 1 (which you agreed was fine), h cannot
be divided by 7 before multiplying by 6.

What are you talking about?
Who is trying to divide h by 7?
Not me. I multiplied it by 7.
======================================
BWAHAHAHAHAHAHA!

You multiplied 1h by 7 and got 6h for the answer. Well done, Bonehead,
and thanks for the laugh!- Hide quoted text -

- Show quoted text -

No, I didn't. 7h - h = 6h.

=========================
Yes you did.
6 * (h/7) -> 5.9\9\ * h but (h/7) is an illegal operation as per my fine
lemma.
What are you talking about, Not thee, thou multipliest by 7?

Try the memory test, it's fun, and you appear to have forgotten you rested
your case:
http://www.bbc.co.uk/blogs/theoneshow/consumer/2009/04/20/how_sharp_is_your_memory_take.html


.

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