Re: How many mathematicians ...

On Apr 22, 11:39 pm, "Androcles" <Headmas...@xxxxxxxxxxxxxxxx> wrote:
....

1/7 = 0.\142857\ + h

If we multiply both sides by 7, we get
1 = 0.\999999\ + 7h
QED.

....

So,

1 = 0.\99999\ + 7h

and earlier

1 = 0.\99999\ + h

Subtracting,

0 = 6h

Therefore h = 0.

I have no problem with that. Or does 7h - h = something special in
Androcles arithmetic?

Uncle Ben

.