Re: Train gedanken pitfall

"Bruce Richmond" <bsr3997@xxxxxxxxxxx> wrote in message news:a5a0205c-cab0-4767-98b4-fa84722a1f7e@xxxxxxxxxxxxxxxxxxxxxxxxxxxxxxx
On Jun 20, 5:26 pm, "Dono." <sa...@xxxxxxxxxxx> wrote:
On Jun 20, 12:17 pm, Bruce Richmond <bsr3...@xxxxxxxxxxx> wrote:





> On Jun 20, 11:04 am, "Dono." <sa...@xxxxxxxxxxx> wrote:

> > On Jun 18, 6:43 pm, Bruce Richmond <bsr3...@xxxxxxxxxxx> wrote:

> > > BTW, your sync by slow transport assumes that moving the clock does
> > > not affect its setting. It is generally accepted that SR agrees > > > with
> > > that assumption, but I can show otherwise. Put the clock on a > > > moving
> > > train Next to the clock at A' and sync it with that clock. Slowly
> > > transport it along the train and place it next to the clock at B'.
> > > According to SR the transported clock must now be in sync with the
> > > clock at B'.
> > > From the tracks we see that the clock at B' is out of
> > > sync with the clock at A', so the setting of the transported clock > > > had
> > > to change as it was transported to be in sync at its new location.
> > > We are not talking about time dialation here.
> > > Transport the clock back
> > > to A' and the setting reverts back so that it is in sync with the
> > > clock at A'.

> > No. It will not. See my post to Whoever- Hide quoted text -

> > - Show quoted text -

> I can show that it does happen using the LT, but I'm not going to
> waste my time for nothing. How about if I show you and you can't pick
> out any error you will admit that you didn't know what you were
> talking about? :)

I'll pick the error , don't worry about it. So, let's see your
computations.- Hide quoted text -

- Show quoted text -

Ok, I'll trust you not to renege on your part of our agreement.

At t=0 A' is at x=0 and the train is traveling at .1c along the x axis
as measured in the track frame.

B' is also on the train at .1 light seconds along the x axis as
measured in the track frame.

The LT says t'=(t-vx/c^2)/sqrt(1-v^2/c^2)

I used units of c to simplify things. With c=1 the c^2 terms go
away. Plugging in the info for B' at t=0 we get

t'=(0-.01)/sqrt(1-.01)

t'=(-.01)/sqrt(.99)= -.010050378

At t=0 the clock at A' read

t'=(0-0)/sqrt(.99)=0

So in the track frame the clocks at A' and B' have different
readings at t=0. They are not is sync in the track frame.

We all agree with that .. assuming A' and B' are in sync in the train frame

Are you still with me? Any errors yet?


.

Relevant Pages

  • Re: Train gedanken pitfall
    ... your sync by slow transport assumes that moving the clock does ... In the train frame A', B' and C' are all in sync, and moving C' by ...
    (sci.physics.relativity)
  • Re: Error Code 13: Guide Info Will Not Download
    ... austin, tx ... Also I had the time sync issue resolved yesterday, ... The internet connection and firewall can be ruled out as suspects. ... internet connectivity and system clock can be ...
    (microsoft.public.windows.mediacenter)
  • Re: WTF with my computer clock?
    ... You may need to build a real LF antenna, ... ethernet port on one end for NTP sync and a 60kHz transmitter to sync a ... clock on the other. ...
    (sci.electronics.repair)
  • Re: Why SR? (was: Source Independency of Light Speed Without an Aether???????)
    ... >>> If the coordinate system is constructed using light ... > Well you could defer to the sync of another frame. ... And if you DID adjsut the tick rate (which is not really what is covered by clock sync) .. ... Would comparing wavelengh of light in each direction and seeing that they are the same, show isotropy of light, without and clock being required ?? ...
    (sci.physics.relativity)
  • Re: Train gedanken pitfall
    ... Put the clock on a>>> moving ... >>> train Next to the clock at A' and sync it with that clock. ... >>> transport it along the train and place it next to the clock at B'. ... as measured in the track frame. ...
    (sci.physics.relativity)