Re: An Embarrassing Question for Relativists

On Oct 31, 2:12 am, HW@..(Henry Wilson DSc). wrote:
On Sat, 31 Oct 2009 12:01:09 +1100, "Inertial" <relativ...@xxxxxxxx> wrote:
"Henry Wilson DSc." <HW@..> wrote in message
news:n3kme5d88tqs5fucd6nia6rr5ckkhjpuoh@xxxxxxxxxx
On Fri, 30 Oct 2009 07:24:50 -0700 (PDT), rotchm <rot...@xxxxxxxxx> wrote:

Look at the diagram I drew in the original message. YOU are the third
observer.

The light from S1 approaches O2 at c-v.

No it does not. Or, perhaps it does. I depends on what *you* mean.
Your sentence is ambiguous and has different interpretations. Make it
more clear: specify who is the observer ( specify relative to which
frame).

The light from S2 approaches O2 at c.

This sentence is a little more clear since it has basically has only
one possible interpretation.

How by any stretch of the imagination can anyone claim that the two rays
are
traveling at the same speed?

They are:

Wrt O1, *the* ray(s) are approaching O1 with speed c, no?
Wrt O2, *the* ray(s) are approaching O2 with speed c, no?

Now...

Wrt O1, the *closing speed* between (the ray and O2) is c-v.

Understand the difference?

We are not talking about the *speed* of a ray. We are talking about
*closing speed*, a totally different concept ( which has nothing to do
with SR by the way).

We are not talking about the speed of *a ray*. We are talking about a
difference of speeds of *two* objects.

That doesn't alter the fact that if a particular observer sees two rays
closing
on a particular observer at different speeds those rays cannot possibly be
traveling at the same speed.

But he doesn't

If a source is at rest wrt  an observer, its light MUST close on that observer
at c.

Nonsense.

Any claim that it doesn't is bogus.

Don't be ridiculous. You just don't know the meaning of the term
"closing speed".




Henry Wilson...www.scisite.info/index.htm

       Einstein...World's greatest SciFi writer..

.

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