Re: Wave Function of the Universe?
- From: "Seratend" <ser_monmail@xxxxxxxx>
- Date: Tue, 31 May 2005 06:37:54 +0000 (UTC)
Arnold Neumaier a =E9crit :
> >
> > You seem to be definitively a lover of the deterministic description
>
> Yes. I believe that there is something deterministic about the universe=
!
>
: )
I prefer to say that deterministic and statistical description are just
two equivalent ways of giving predictive results: I accept both.
Decribing a function by its points or by its induced probability law is
somewhat equivalent (2 point of views).
> In the 1925 physics views, it is discrete.
> In the post 1975 physics, it is again continuous, since the basic
> objects in the universe are quantum _fields_, and particles
> only arise through some ill-understood process, unless the field is
> free and the two descriptions are equivalent.
>
Well as I have a finite capacity brain, I just can understand/see
dicrete and finite quantities (I have never handled an infinite
quantity except in the math and physics models). Therefore It seems
that I prefer to view (choice) the world closer to the 1925 view (woaw!
I didn't think I have a so obsolete point of view ; ).
Even if the fields are continuous, the observables, at least what we
[can] measure is discrete. Therefore, the impossible anwser is to know
if the set of all possible measurable values of a given "real"
observable is countable or uncountable.
However, in any case, choosing a discrete or continuous model will give
the same results at the limit (huge number/small size).
And I must admit, making predictions when the particle number is not
conserved is already difficult in the QFT formalism. I just can
imagine, it would be a nightmare with a pure discrete approach (and may
be, a waste of time and not very interesting from a calculus point of
view ; ).
However, I prefer to view the universe as finite and discrete
(~epistemic/practical view): all the mathematical problems of
infinities dissappear and I may question mathematical results on
infinities whenever the limit is not continuous.( Note that, most of
the time I prefer the continous model for mathematical predictions ; ).
Seratend.
.
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