Re: Is algebraic holography cheating?

From: very_cryptic@xxxxxxxxxxx
Date: Sun, 14 Aug 2005 17:28:53 +0000 (UTC)

A minor correction:

>While it's true that there are no local degrees of freedom in a
> diffeomorphic covariant theory

I left out the word "observable". I meant there are no local
observables.

.

References:
- Is algebraic holography cheating?
  - From: very_cryptic

Prev by Date: Re: The time it takes to emit one photon
Next by Date: Re: What is the 'Unruh Effect'?
Previous by thread: Is algebraic holography cheating?
Next by thread: meet the A^b Forward/backward anomaly
Index(es):
- Date
- Thread