Re: What is quantum measurement problem?

I wrote:

> > That implies the outcome of a measurement depends on the state of the
> > apparatus, thus isn't determined by the measured system and
> > probabilities alone like according to quantum mechanics.

"Chris H. Fleming" <chris_h_fleming@xxxxxxxxx> a écrit dans le message de
news: 1132180817.231976.286810@xxxxxxxxxxxxxxxxxxxxxxxxxxxxxxx

> Probabilities come from Born interpretation. The Schrödinger equation
> is fully deterministic. If you use the Schrödinger equation alone and
> model the entire apparatus and measurement process as interaction, then
> yes.

The Born (rather Copenhagen) interpretation implies a projection onto the
eignestate.

> > There must already be a
> > discontinuous process in the system alone to drive the apparatus
> > (irreversibly) to the configuration corresponding to the eigenvalue.

> It is as discontinuous as the decoherence time is small.

Therefore not discontinous, see the definition. And decoherence depends on
the state of the surrounding. Both approaches aren't reconciliables.

> We might as well attempt to see if it works before throwing our hands in
> the air.

I don't forbid you to try, it's your time.

--
~~~~ clmasse on free F-country
Liberty, Equality, Profitability.


.

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