Re: Does EPR require entanglement?
- From: Cl.Massé <postmaster@xxxxxxxxxxxxxxxxxxxxxx>
- Date: Sun, 16 Apr 2006 20:36:58 +0000 (UTC)
"Vonny N." <vonnyn@xxxxxxxxxxx> a écrit dans le message de news:
1144986615.387607.247090@xxxxxxxxxxxxxxxxxxxxxxxxxxxx
In particular, if a compound system has a total
spin of zero, then I would have thought the spin in any direction is
conserved in *any* state, not just the entangled ones.
An non entangled state of spin 0 is made of a particle in a definite spin
state, and the other particle in the opposite definite spin state. But an
entangled state may be the superposition of such states.
In the Hilbert space language, a non entangled state of spin 0 is hx-h. A
entangled state of spin 0 is h1x-h1 + h2x-h2 + ... , which isn't expressible
in the form hxk.
The outcome of a measurement in a non entangled state will always be the
same, therefore the spin is conserved. In the case of an entangled state,
the outcome won't always be the same, but will be correlated, so that the
total spin is conserved.
The difference between the two cases could be labelled "local" or "global"
conservation.
--
~~~~ clmasse on free F-country
Liberty, Equality, Profitability.
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