Re: Two-slit experiment
- From: bz <bz+spr@xxxxxxxxxxxxxxxxxxxx>
- Date: Fri, 23 Jun 2006 12:36:58 +0000 (UTC)
"drspeg" <drspeg@xxxxxxxxxxx> wrote in
news:R62dnftk_8SSZQrZnZ2dnUVZ_qadnZ2d@xxxxxxxxxx:
I've been looking for an answer to two questions regarding the 2-slit
experiment (showing both wave and particle properties of light). I hope
someone here might know how to respond.
Quick review of what I believe I know: Shooting a single photon (or
electron) at a wall that contains two slits will result in an
interference pattern on the wall (detector plate) beyond the holes.
Wrong. A single photon will produce a single point response somewhere on
the detector plate. The probability of hitting any one point can be
determined by accumulating data from a series of single photons(or
electrons).
A series of single photons will build up a pattern similar to that seen
when a continuous stream of photons is used.
Blocking one hole results in an accumulation pattern.
When one hole is blocked, and a series of single photons is used, the
accumulation pattern will look similar to that seen when a continuous
stream of photons is used with a single slit.
When both holes
are open, detecting which of the two holes the electron passes through
results in an accumulation pattern (uncertainty is violated).
(1) Does obtaining an interference pattern depend at all on the timing
of the electron gun shooting each new electron? Or would the
interference pattern still obtain even if you shot one electron a day
for many days (and were able to record the impacts of electrons on the
detector plate)?
Appears to be rate independent. Photon(Electron) multiplyer arrays can be
used to capture and record the location of the impacts over a long period
of time.
(2) If, in the case where one determines through which slit each
electron passes, one were to replace the detector plate with ANOTHER
wall containing two slits, would uncertainty be restored? That is,
knowing through which slit electrons first pass should produce an
accumulation pattern, but if that pattern were displayed on a wall
containing two slits (in this case the experimenter does NOT determine
through which slit the electron passes) would an interference pattern
occur?
Perform the experiment and see.
So, in this double-two-slit experiment, determining the first "choice"
made by the pasing electron, but not the second... would there be an
accumulation pattern followed by an interference pattern?
Thanks!
--
bz
please pardon my infinite ignorance, the set-of-things-I-do-not-know is an
infinite set.
bz+spr@xxxxxxxxxxxxxxxxxxxx remove ch100-5 to avoid spam trap
.
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