Re: Gravitational redshift


Thomas Palm wrote:
WG <wgilmour@xxxxxxxxxx> wrote in news:1153180335.343568.262620
@i42g2000cwa.googlegroups.com:

A more succinct way to state this problem would be;

If you take a sphere of density d and imbed it in a background density
of d1, where d=d1, would you still get a redshift?
[i.e. does redshift approach 0 when d approaches d1, or d approaches 0
(it has to be 0)]

The answer has to be yes, you still get a redshift for the following 2
reasons.

1. From Zg = 4.19 G d r^2/c^2
For a given r, Zg can only approach 0 when d approaches 0.

2. From Gausses theorem, the matter [i.e. density] outside r
does not come in to play, the theorem makes it irrelevant,
it could be 0,
extremely large or anything in between including d.

To make things a bit more tricky: if you get a redshift sending light away
from the center of that sphere, surely you must get a blueshift if you send
it the other way, towards the center. But if the density is in reality
constant you can create spheres with any center you wish so that light that
travels away from the center of one travels toward the center of a
displaced sphere. Will it be red- or blueshifted?


Yes, I had previously thought of this argument and it is a good one.
The only thing I can suggest is that the symmetry of the argument may
be broken here and the 2 cases different..

In order to get a blueshift you need an observer sitting in the middle
of his visible horizon [i.e. potential well] and the photon has to be
created somewhere closer to the edge of this well and travel inward. In
this case the photon would clearly feel that there is more mass in the
direction of the observer, and thus blueshift occurs. In the photons
reference frame however there is not more mass in one direction since
it sits at the middle of its own visible horizon. [read well], also the
gravitational forces act on the moving photon not the observer so this
should be the only consideration.

This may be unsatisfactory but it's the best I can do for now.
In any case this still does not resolve my initial argument.

This idea does suggest one other point.
Why is the value of C what it is?
What if the minimum kinetic energy of a photon be exactly equal to the
minimum required to raise it out of the potential well of the universe?
This is a Mach's principle type of argument which states that the
properties of matter [inertial] are a result of the gravitating mass of
the universe as a whole.
This sets the value of C according to the value of the mass of the
universe out to the visible horizon.

For the complete argument please visit;
http://home.i-zoom.net/~wgilmour/Machs%20Principle.html
It also suggests a VLS theory.

.

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