Re: A question of efficiency
- From: Richard Saam <rdsaam@xxxxxxx>
- Date: Thu, 10 Aug 2006 00:30:46 +0000 (UTC)
rfellows00@xxxxxxxxx wrote:
I been reading here for a few weeks. All else held constant andI thought there would be more discussion on this post:
comparing apples to apples...If your goal is to have maximum wind speed
over a controlled cubic area within a cylinder and your biggest
constraint is cost of electricity consumed, would you "push" the air
through the controlled area from a blower at the entrance of the
cylinder OR "pull" the air through from a blower at the exit.
Thank you in advance. Ronnie
Analysis:
System A 'pulling'
P1 P3 P1
---------------------------------
/\ ^ <--
/ \ | <--
\ / | <--
|| |D QA = Q <-- vA
/ \ | <--
\ / | <--
\/ v <--
---------------------------------
<- L ->
System B 'pushing'
P1 P3 P1
---------------------------------
^ <-- /\
| <-- / \
| <-- \ /
QB = Q |D <-- vB ||
| <-- / \
| <-- \ /
v <-- \/
---------------------------------
<- L ->
Governing equations:
1. vA is average velocity in System A 'pulling' volume (V)
2. vB is average velocity in System B 'pushing' volume (V)
2. P2 - P1 = rhoB (L / D) vB^2 / 2
3. P1 - P3 = rhoA (L / D) vA^2 / 2
4. V = (pi / 4) D^2 L (V is Volume where VA = VB)
5. P V = n R T (air compressiblity
or expandibility)
or
P = (n / V) R T = (rho / M) R T
6. Power = P Q (Q is flowrate and QA = QB)
Therefore:
rho = (P1 + P2)/2 M / (R T)
and
P2 - P1 = (P1 + P2)/2 M / (R T) (L / D) vB^2 / 2
= (P1 + P2) k vB^2
and
P1 - P3 = (P1 + P3)/2 M / (R T) (L / D) vB^2 / 2
= (P1 + P3) k vA^2
rearrange:
k vB^2 = (P2 - P1)/ (P1 + P2)
k vA^2 = (P1 - P3)/ (P1 + P3)
As defined:
P2 > P1 > P3
let for example:
k = 1 P1 = 10 P2 = 11 P3 = 9
then:
vB^2 = (11 - 10)/ (10 + 11) = 1/21
vA^2 = (10 - 9)/ (10 + 9) = 1/19
therefore:
vA > vB
Due to air expandibility
Condition A 'pulling' results in faster velocity vA
than air compressiblity
Condition B 'pushing' resulting in slower velocity vB
The power is the same for A and B
Power = (P2 - P1) Q = (P1 - P3) Q
but 'power / mass' in volume 'V'
is just the opposite of 'power / velocity'.
power/(rhoA V) > power/(rhoB V)
Richard Saam
.
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- A question of efficiency
- From: rfellows00
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