Energy loss in a capacitor



This is a typical problem in undergraduate physics: When a charged
capacitor in connected to an equal uncharged capacitor through a
resistor, the final energy in the capacitors is less than the initial
energy. This loss in energy is dissipated in the resistor as heat
(Joule Heating). Now if the capacitors are connected with
resistanceless wires (superconducting, for example), then the deficite
in energy has to be explained as energy radiated as electromagnetic
waves (due rapid change in current).
My question is, why do we consider the deficite energy to be dissipated
only as heat when a resistor is connected? Because even in this case,
due to non-linear variation of current, some energy is bound to get
radiated away. Is this because its amount is negligible? Do the laws of
Electromagnetism entail preference for Joule Heating over radiation?
Can anyone shed light on this ??

.



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