Re: Atomic electrons

On Jan 10, 5:51 pm, Richard Saam <rds...@xxxxxxx> wrote:
Igor Khavkine wrote:
On Jan 7, 8:00 am, Phil Gardner <pej...@xxxxxxxxxxx> wrote:

Atomic electrons spr

The currently accepted atomic model (nucleus + electron cloud) assumes
that every electron that can be ejected from a ground state atom or
atomic ion in any low energy collision with an atom, ion or particle
exists as an electron in that ground state.  There would seem to be no
way in which this assumption can ever be tested by experiment.

How about using x-ray scattering to determine the charge distribution
of an atom at any given level of ionization? The spread of the charge
distribution of a nucleus is known to be much smaller (about 10^5
times smaller) than the spread of the charge distribution of an atomic
electron. So, if I understand correctly the assumption you are talking
about, it's certainly experimentally testable.

Google "x-ray scattering" or "x-ray spectroscopy". Computational
chemistry is a major industry, with electronic structure calculation
as one of its main goals. They wouldn't get very far if they couldn't
compare their calculations to experiments.

Igor

We have to be clear here that X-ray Mev scattering will establish the
positions of atomic nuclei (Bragg Peaks) within some type of crystalline
or polymeric structure but will not provide much if any information on
electron distribution (ev energies) around any particular atom.  Lower
energy ev electrons are required as per the work of Murray Arnow.

Determining atomic electron cloud structure with X-rays would be like
determining a cumulus cloud structure with a M50 rifle.

Richard- Hide quoted text -

- Show quoted text -

But isn't that what X-Ray diffraction is all about? X-Rays are
scattered primarily from the electrons. It is the cloud of electrons
around the nuclei that diffract the X-Rays. Although the obvious
structure of an X-Ray diffraction image is due to the periodic
structure of the crystal, I am under the impression (but I'm not that
knowledgable about it) that there is information in the brightness of
the individual dots that gives information about the distribution of
electrons in the clouds.

Maybe it is like studying clouds of sand with an M50 rifle...

Rich L.

.

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