Re: Does the Electron Neutrino Have Mass and Charge?

From: kenseto (kenseto_at_erinet.com)
Date: 06/28/04 

Date: Mon, 28 Jun 2004 08:43:00 -0400

"Bjoern Feuerbacher" <feuerbac@thphys.uni-heidelberg.de> wrote in message
news:cbotdh$nb1$1@news.urz.uni-heidelberg.de...
> kenseto wrote:
> > "Bjoern Feuerbacher" <feuerbac@thphys.uni-heidelberg.de> wrote in
message
> > news:cbe7sa$bko$1@news.urz.uni-heidelberg.de...
> >
> >>kenseto wrote:
> >>
>
> [snip]
>
>
> >>>If an observer is moving along side of an electron neutrino he will
> >>>measure it to have the same mass and charge as an electron.
> >>
> >>How would he do such a measurement?
> >
> >
> > Obviously he can't.
>
> Why not?

Because he would have to accelerate to the same state of absolute motion
 as that of the electron-neutrino
>
> And if he can't, why did you say above what he will measure?

Because that's what MM predicts.
>
>
> >>And how does a motion of the observer relative to the neutrino affect
> >>this? Be quantitative, please. Let v be the velocity of the observer
> >>relative to the neutrino. Let m(v) and q(v) be the measured mass and
> >>charge. What do you predict for m(v) and q(v)? You already said
> >>that m(0) = m_electron and q(0) = q_electron, but that is not very much
> >>information...
> >
> >
> > That's why I suggest the scattering experiment with the electrons and
the
> > neutrinos moving in the opposite directions. If the the scattering is
the
> > same as the electron-electron scattering then we can conclude that
> > the neutrino has the same mass and charge as the electron.
>
> You did not answer my question. What does MM predict for m(v) and q(v)?

MM only predicts that m(0)=m_electron and q(0)=q_electron.
m(v) and q(v) are not measureable because the neutrino and the electron
have different states of absolute motion.
>
>
> >>>>>>What is this "rarely detected" you talk about??????
> >>>>>
> >>>>>
> >>>>>Because a neutrino have a higher state of absolute motion than
> >>>>>ordinary electron the distortion it impart on the E-Matrix is
> >>>>>dissipated by the time the electron is in a position to interact with
> >>>>>it Therefore its charge and mass are rarely detected.
> >>>>
> >>>>Why on earth do you think that its charge and mass are "rarely
> >>>>detected"?????????
> >>>
> >>>
> >>>Because it has a higher state of absolute motion. The distortion it
> >>>impart in the E-Matrix is already dissipated by the time a normal
> >>>electron is ready to interact with it.
> >>
> >>*sigh* And again you misunderstand my question. I didn't ask because
> >>of what reason you predict this. I asked why you think that this indeed
> >>*happens* in nature!!! I did not ask what you think about why this
> >>happens!!! Try to understand the difference between these two questions,
> >>please.
> >
> >
> > Hey idiot that's what MM says how it happens.
>
> And *still* you don't understand what I ask.
>
> I do *not* ask what MM predicts. I ask why you think that this really
> *happens* in nature!!! Why do you think that the charge and mass
> of the neutrino are "rarely detected"?

<sigh> I already told you why....the distortion in the E-Matrix caused by
the
the neutrino is already dissaipated by the time the electron is moved into
position to react to it. The only time an electron is in a position to react
to
the neutrino's distortion is when they are moving directly in the opposite
direction
and that's why the mass and charge of the neutrino are "rarely dectected"
>
> This is a question of what you know about the *results* of the
> *experimental tests*, *not* about what MM predicts!!!
>
>
>
> Please tell me how measurements of the neutrino mass are actually done,
> in your opinion.

Do the neutrino and electron scattering experiment in the opposite
directions
as I suggested. The result should be that the neutrinos will scatter the
elctrons
similar to that of an electron-electron scattering and thus confirming that
a neutrino
have the same mass and charge as that of an electron.

Ken Seto

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