Re: Aether is the empty space in which the Universe sits
From: David Thomson (_at_)
Date: 07/18/04
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Date: Sun, 18 Jul 2004 15:39:18 -0500
"Bilge" <dubious@radioactivex.lebesque-al.net> wrote in message
news:slrncfi9ot.26e.dubious@radioactivex.lebesque-al.net...
> David Thomson:
> >"MorituriMax" <newage@sendarico.net> wrote in message
> >news:DhdJc.54378$W6.33927@fe2.texas.rr.com...
> >> How the hell do you "find" it if it is not detectable?
> >
> >You quantify empty Aether by observing the stuff that passed through it.
>
> So, I take it that a particle with an initial trajectory along the
> axis of a piece of beam pipe under vacuum, should scatter and hit the
> edge of the beam pipe? Assuming a vacuum of 10^-6 torr and an electron
> of energy E, what contribution to the scattering would be represented
> by the ether? At 10^-6 torr, the mean free path is extremely long, so
> for the most part, you shouldn't have to worry about scattering from
> the residual gas.
Forget the trajectory stuff. At that level of existence you are already
beyond the level of Aether and dealing with compound structures. If you
want to know the geometrical constant that governs the Aether you need to
look the different types of charge first. If you can't recognize the strong
charge of the subatomic particles in your physics theory, then you won't
recognize the Aether. A unit of Aether is equal to a 2 spin rotating
magnetic field. In order to see this you need to understand
electromagnetism, not the momentum of electrons and photons.
The Compton scattering of photons against electrons reflect the various
angles photons would scatter off of electrons. The scattering angle is
equal to (1-cos(theta)) where theta is the incident angle of the photon.
Producing a plot for these angles yields a cardioid pattern, which reflects
the actual shape of the electron when seen from the perspective of a single
frame of time. This pattern indicates part of the shape of the Aether
rotating magnetic field seen from a particular viewpoint, since the
subatomic particles take their shape from the Aether.
This can all be mathematically and graphically represented.
> >You quantify empty Aether by the force it exerts on physical objects
> >(Coulomb's constant, Newton gravitational constant).
>
> OK, If I place a charge out in space somewhere, what force will
> the ether exert on it and which direction will it accelerate?
The force is exerted on two objects. The Aether is a 2 spin rotating
magnetic field that draws charge together or pushes it apart, depending on
the nature of the charge. Aether is not a particle, so it doesn't interact
with particles.
> >You quantify empty Aether by observing the empty "fields" it makes in
the
> >presence of a magnet.
>
> What's an ``empty field'' (other than kook research)?
Any magnetic field in a vacuum is an empty field. It is empty in the sense
that there are no subatomic particles in the field, and yet the field is
composed of magnetically aligned Aether units. Being the source of charge,
Aether itself has charge, although its dimensions are reciprocal to the
charge dimensions of particles. It's like time and frequency are
essentially dimensions of time, except that one is the reciprocal of the
other.
> >You quantify empty Aether by observing the macro shapes that occur
> >from the subatomic matter that occupies it.
>
> Such as?
Such as the Compton scattering of photons striking electrons.
> >You quantify empty Aether by the curvature of light as light passes by
large
> >masses (like stars).
> >Aether is pulled into mass due to the binding of subatomic particles.
> >If the mass is spherical, the bending of spacetime will also be
spherical.
>
> Starting with these so-called sub-atomic particles that bind, how
> about performing a calculation that shows how much bending occurs?
I've got the equation for the neutron binding worked out exactly. But this
is one equation that I will reveal through my upcoming book. It requires
far more presentation than can be done online in text.
> >The Morley - Miller experiment was conducted between mountain tops,
because
> >they thought maybe the Aether was connected to the basement of the
> >Michelson - Morley experiment. But as it turns out, the Aether is also
> >connected to the atmosphere between the two mountains. Both experiments
are
> >proof that Aether is composed of quantum units of spacetime, each
> >independent from the other. Each quantum particle (electron and proton)
> >needs one Aether unit. (Neutrons need two, being a composite of an
electron
> >and proton.)
>
> I'm sure you won't believe this, but the electron spin is 1/2, the
> proton spin is 1/2, the neutron spin is 1/2 and 1/2 + 1/2 can only
> add to 0 or 1.
I know you won't believe this, but electrons and protons get their 1/2 spin
from the Aether. When a neutron forms, two Aether units, one carrying the
proton and the other carrying the electron, overlap each other. The effect
is spacetime is folded and the two particles produce a single particle still
having 1/2 spin. The anti-neutrino also ends up with 1/2 spin and your
forgot to include that.
The binding process of the neutron is different from the binding process of
nucleons in the way the particles share spacetime.
Like I said, I know you won't believe it because you already have everything
figured out.
> >As protons, neutrons, and electron bind with each other, they
> >fold Aether in upon itself. This causes the so-called gravitational
lensing
> >effect around massive objects.
> >
> >It was assumed by the scientists of the late 1800s that the Aether would
be
> >like a loose wind, blowing through matter. But stable physical matter
> >cannot exist apart from the Aether and thus the two act upon each other.
>
> A calculation please.
I've spent the last 5 months putting all the equations, and graphics into a
book. I've got the rough draft done and am now finishing it off. I expect
to have the manuscript sent out for peer review in mid September (yes, there
are actually physicists with PhDs in this country who see the value of what
I have done.) The published book is expected to be on the market by late
December.
> >Neutrinos can exist apart from the Aether, that is why we can't detect
their
> >mass.
>
> La-de-da... search google for super kamiokande.
La-de-da, I have. I have quoted the authors of the Super-Kamiokande
experiment in my book.
> >Neutrinos are passing in between Aether units and unless they strike
> >a neutron, don't interact with physical matter.
>
> Then how is it that experiments have measured electron-neutrino
> scattering? Just a fluke?
You're reading too much into the "research" papers. Nothing has been
confirmed to the precision of the Compton scattering. The scattering angles
don't even match the expected Weinberg angle of sin^2theta. It's not a
fluke, it just hasn't been conclusively proved.
> >When neutrinos strike a
> >neutron, all they do is knock the anti-neutrino loose and cause the
electron
> >to fly loose due to it relatively huge magnetic moment. Thus the mass
of
> >the neutrino is really 1.531 times greater than the electron.
>
> Gee, that's interesting, since it doesn't show up as the beta endpoint
> energy on a kurie plot. I guess neutrinos accomplish this by violating
> conservation of energy and momentum.
Just as do the "vitual photons" from the Casimir effect. Bohr was right,
conservation of energy and momentum does not apply at the subatomic level
with regard to neutrinos. The evidence clearly shows that the neutrino mass
and angular momentum should be 1.531 times the electron. And the evidence
just as clearly shows that the neutrino mass and angular momentum are not
there. Having a preconceived idea that neutrinos must observe a man-made
law of physics is the absurdity here, not the violation of that man-made
law.
Dave
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