Re: Gravity Inside A Cylinder
From: kdthrge (kdthrge_at_yahoo.com)
Date: 08/22/04
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Date: 21 Aug 2004 18:12:50 -0700
"> >
> > Zero G at the longitudinal axis, in the middle only , move off a bit and
> > you go to the wall.
> >
> > Do a vector sum, (integral actually) of forces from the cylinder wall to
> > each interior point.
> >
>
> Hmm. Intriguing :) Crap at math as I am, I had naively assumed that the
> cylinder's circular cross section would cause a similar result to that of
> being inside a spherical shell; in which our object would feel no attraction
> towards the walls regardless of where it is. From the exact centre of our
> object, shine two identical torch beams in opposite directions; the one that
> hits the further wall would cover a larger area than its sibling, but due to
> the inverse square law the gravitational attraction created by the area it
> covers would be weaker. In a spherical shell, the two effects neatly cancel
> out. Why not in our cylindrical one?
>
> Ian
This calculating is done purely equating the structure of the matter
as equally inducing force of gravity. A body which is bound together
by gravitation, more likely produces a gravitational field in which
there will be greater density of field at the common center of mass.
The effects of gravity suggests this. The inverse square law does not
have to be modified as one approaches the surface of the earth and the
angle to the limbs of the earth(horizon) becomes 180 degrees.
If the gravitational field has higher density in the center, then
there will be greater and greater acceleration until one reaches this
point in the theoretical cylinder of finite length. This would produce
a velocity far above escape velocity of the attracting body of
mass.(about 5 times greater) Any spin or lateral motion and tidal
forces will rip apart the falling body before it reaches the center.
It will not survive passing through the center either. If tidal forces
do not rip it apart, the heat produced by the gravitaional force
acting against the momentum will cause it to melt or ionize.
http://home.earthlink.net/~kdthrge
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