Re: Gravity Inside A Cylinder

From: kdthrge (kdthrge_at_yahoo.com)
Date: 08/22/04 

Date: 21 Aug 2004 18:38:01 -0700

> >
> > Zero G at the longitudinal axis, in the middle only , move off a bit and
> > you go to the wall.
> >
> > Do a vector sum, (integral actually) of forces from the cylinder wall to
> > each interior point.
> >
>
> Hmm. Intriguing :) Crap at math as I am, I had naively assumed that the
> cylinder's circular cross section would cause a similar result to that of
> being inside a spherical shell; in which our object would feel no attraction
> towards the walls regardless of where it is. From the exact centre of our
> object, shine two identical torch beams in opposite directions; the one that
> hits the further wall would cover a larger area than its sibling, but due to
> the inverse square law the gravitational attraction created by the area it
> covers would be weaker. In a spherical shell, the two effects neatly cancel
> out. Why not in our cylindrical one?
>
> Ian

This calcualting is done purely considering that the mass of the
structure is equally producing the force of gravity. A body bound
together by gravitation more likely produces a gravitational field
which has higher density at it's center of mass. The effects of
gravity suggest this. The inverse square law does not have to be
modified as one approaches the surface of the earth and the angle to
the limbs of the earth (horizon) becomes 180 degrees. This would be
very apparent in the orbit of satelites.
If the gravitational field is greater at the center of mass, then
there will be greater and greater acceleration on the falling bady as
it reaches the center of mass of the theoretical cylinder of finite
length. This will give it a velocity far above the escape velocity for
this bady of mass. Any spin, or lateral motion from dead center, and
tidal forces will rip it apart before it reaches the center. It will
not survive passing through the center. If tidal forces don't rip it
apart, then the heat generated from the gravitation acting against the
momentum will cause it to melt or ionize.

http://home.earthlink.net/~kdthrge

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