Re: what is the relation between force and energy?

From: Andr? Michaud (srp_at_microtec.net)
Date: 09/28/04 

Date: 28 Sep 2004 15:59:10 -0700

sbharris@ix.netcom.com (Steve Harris sbharris@ROMAN9.netcom.com) wrote in message news:<79cf0a8.0409281049.269e90d9@posting.google.com>...
> Bjoern Feuerbacher <feuerbac@thphys.uni-heidelberg.de> wrote in message news:<cjb7vn$3io$1@news.urz.uni-heidelberg.de>...
> > Steve Harris sbharris@ROMAN9.netcom.com wrote:
> > > srp@microtec.net (Andr? Michaud) wrote in message news:<562f286c.0409270243.5f19719a@posting.google.com>...
> > >
> >
> > [snip]
> >
> >
> > > Well, you seem to think you can use E = h*f
> > > for electrons in a Bohr orbit, but that equation applies to photons
> > > only.
> >
> > Slight correction: E=h*f applies also to electrons, not just to photons
> > (the time-dependent wave function for electrons has a factor
> > e^(-iEt/h), with E=hf). Where he went wrong is in inserting the orbital
> > frequency of a ground state Bohr electron for f! *That* makes no sense.
> > Essentially, one would have to insert for E the rest mass of the
> > electron, subtract the binding energy from that, and then one can
> > get f from f=E/h.
>
>
>
> COMMENT:
>
> Yes, of course you're right that you can use E=hf for the electron if
> E is the total energy, which includes the rest mass.

No. In E=hf for the Bohr orbit, E includes only the energy induced
by the force.

That's precisely what Davisson and Germer confirmed at the Bell Telephone
lab.

They found that x-rays of the same wavelength calculated from the
velocity of electrons with the deBroglie equation deflected with
the same angle as the electrons. X-rays, not gamma rays.

André Michaud

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