Re: How to tell if a theory is a good one
From: Bill Hobba (bhobba_at_rubbish.net.au)
Date: 10/12/04
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Date: Tue, 12 Oct 2004 23:47:42 GMT
"Cadwgan Gedrych" <cadwgan_gedrych@yahoo.com> wrote in message
news:5e1797c9.0410120646.4cfed45f@posting.google.com...
> "Bill Hobba" <bhobba@rubbish.net.au> wrote in message
news:<9KJad.22920$5O5.3441@news-server.bigpond.net.au>...
> > "Cadwgan Gedrych" <cadwgan_gedrych@yahoo.com> wrote in message
> > news:5e1797c9.0410110527.7952fe45@posting.google.com...
> > > "robert j. kolker" <nowhere@nowhere.net> wrote in message
> > news:<2so0n5F1mpsehU1@uni-berlin.de>...
> > > > Cadwgan Gedrych wrote:
> --snip--
> >
> > As is typical of those that do not understand relativity they
> > think it is a theory to do with light - it is not. It is a
> > theory of space-time symmetry. See the links I have given
> > previously in this thread.
> >
> > Bill
>
> I can easily be much more general than "with light," and I can
> easily by-pass your "space-time symmetry" claim by merely
> pointing to the simple fact that all 2-clock measurements in
> SR are incorrect because Einstein's clocks are incorrectly
> related temporally. This of course includes the t, t', v, and
> c of SR's transformation equations, which of course invalidates
> them.
I can easily bypass your objection by simply noting SR does not depend on
Einstein clocks (whatever they are) as the many links I have given
previously to you in this thread demonstrate. The derivation in those links
derive SR not from any assumption about clocks but from the POR and symmetry
properties. For example the symmetry properties of an inertial frame
implies that stationary clocks in an inertial frame once in sync remain in
sync. It is a well known mathematical theorem that SR is as consistent as
Euclidean geometry.
Bill
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