Re: Invariant Galilean Transformations (FAQ) On All Laws

From: eleaticus (eleaticus_at_bellsouth.net)
Date: 10/18/04 

Date: Sun, 17 Oct 2004 19:45:42 -0500

"Gregory L. Hansen" <glhansen@steel.ucs.indiana.edu> wrote in message
news:ckuu9i$m65$1@hood.uits.indiana.edu...
> >On the other hand, velocity v definitely is not invariant under the
> >transformations; it is relative to one of the coordinate systems.
> >
> >L = x0 + ut.
> >
> >x0 becomes x0-vt and ut becomes (v-u) in the second system.
> >
> >Yet, y'all do not include v in your list of transformations and
xform-based
> >operators.
> >
> >Why? The only excuse is that it is not a transformed coordinate and it is
> >transformed coordinates under discussion.
>
> The reason why is because v=dx/dt. The transformation for v is derived
> from the transformations for x and t. Under a Galilean boost,
>
> v'=dx'/dt' = (dx + u dt)/dt = (dx/dt + u) = v + u

Yet, in my L = x0 + ut, let u=50 and the velocity of the second observer be
100.

Strange, isn't it how your u+v comes out to be 150 instead of the
actual -50?

eleaticus

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