Re: The genius Daryl McCullough strikes again!

From: eleaticus (eleaticus_at_bellsouth.net)
Date: 10/25/04 

Date: Mon, 25 Oct 2004 07:39:34 -0500

"Daryl McCullough" <daryl@ajtc-nycorp.com> wrote in message
news:clildj02rat@drn.newsguy.com...
> eleaticus says...
>
> >"Daryl McCullough" <daryl@atc-nycorp.com> wrote in message
> >news:clgcb4026hh@drn.newsguy.com...
> >> >> If a car is travelling according to x_car = 1/2 a t^2 according to
> >> >> the frame of the ground, and a tree is stationary (x_tree = 0), then
> >> >> what is the position of the tree as a function of time in the frame
> >> >> of the car?
> >>
> >> What's the answer?
> >
> >For the umpteenth time:
>
> For the umpteenth time, you don't give an answer. So
> what did you mean when you said the following?
>
> >Actually, I have demonstrated on these newsgroups that in Newtonian terms
> >objects moving inertially in the view of an inertial observer also move
in
> >straight lines and with equal distances per time unit in the view of
> >accelerating systems.
>
> Are you now agreeing that you were wrong?

You actually, really are insane, aren't you?

I'll give you a clue which would make it quickly obvious to honest people of
competence. Let there be three beacons A,B,C in a straight line and with the
distance from A to B equal to the distance from B to C. Let an inertial
object pass A at t=0 and proceed past B to C. The transit time from A to B
will equal that from B to C.

In the accelerating system note the coordinates at all three times of A, B,
C, transform the 3-coordinates and note that at all times A,B,C are in a
straight line (as evidenced by B'-A' = C'-B'). Hence, the inertial object
did move in a straight line and the object made each sub-transit in equal
times.

eleaticus

 --
> Daryl McCullough
> Ithaca, NY
>

Relevant Pages

  • Re: Lordy, Hobba, get it straight. Or are you that incompetent?
    ... > distance from A to B equal to the distance from B to C. Let an inertial ... > In the accelerating system note the coordinates at all three times of A, ... > did move in a straight line and the object made each sub-transit in equal ... When people post rubbish all I can do is say it is rubbish - no amount of ...
    (sci.math)
  • Re: Lordy, Hobba, get it straight. Or are you that incompetent?
    ... > distance from A to B equal to the distance from B to C. Let an inertial ... > In the accelerating system note the coordinates at all three times of A, ... > did move in a straight line and the object made each sub-transit in equal ... When people post rubbish all I can do is say it is rubbish - no amount of ...
    (sci.physics)
  • Re: Lordy, Hobba, get it straight. Or are you that incompetent?
    ... > distance from A to B equal to the distance from B to C. Let an inertial ... > In the accelerating system note the coordinates at all three times of A, ... > did move in a straight line and the object made each sub-transit in equal ... When people post rubbish all I can do is say it is rubbish - no amount of ...
    (sci.physics.relativity)
  • Re: The genius Daryl McCullough strikes again!
    ... > eleaticus says... ... >>I'll give you a clue ... Let there be three beacons A,B,C in a straight line and with the ... In the accelerating system note the coordinates at all three times of A, B, ...
    (sci.math)
  • Re: The genius Daryl McCullough strikes again!
    ... > eleaticus says... ... >>I'll give you a clue ... Let there be three beacons A,B,C in a straight line and with the ... In the accelerating system note the coordinates at all three times of A, B, ...
    (sci.physics)