Re: Charge
From: Peter Kinane (pkinane_at_iol.ie)
Date: 01/13/05
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Date: Thu, 13 Jan 2005 16:12:13 -0000
"Old Man" <nomail@nomail.net> wrote in message
news:6NudnY4vioIddHjcRVn-qQ@prairiewave.com...
>
> "Peter Kinane" <pkinane@iol.ie> wrote in message
> news:cs4f62$a74$1@kermit.esat.net...
> >
> > "Old Man" <nomail@nomail.net> wrote in message
> > news:jaWdnScCSZnzOXjcRVn-iw@prairiewave.com...
> >>
> >> "Peter Kinane" <pkinane@iol.ie> wrote in message
> >> news:cs408j$5de$1@kermit.esat.net...
> >> > "Bjoern Feuerbacher" <feuerbac@thphys.uni-heidelberg.de> wrote in
> > message
> >> > news:cs3mf9$mfo$1@news.urz.uni-heidelberg.de...
> >> >> Peter Kinane wrote:
> >> >> > "Bjoern Feuerbacher" <feuerbac@thphys.uni-heidelberg.de> wrote in
> >> > message
> >> >> > news:cs3c9b$kmf$3@news.urz.uni-heidelberg.de...
> >> >> >>Peter Kinane wrote:
> >> >> >>>"Bjoern Feuerbacher" <feuerbac@thphys.uni-heidelberg.de> wrote in
> >> >> >>>message news:cs2sj6$9jp$1@news.urz.uni-heidelberg.de...
> >> >>
> >> >> [snip old stuff]
> >>
> >> [snip more stuff]
> >>
> >> > > > So, just to be clear, are you saying that mass - in the context
of
> >> > > > "masses
> >> >> > always attract" - does not effect through, or consist of, or
> >> >> > express,
> >> >> > or
> >> >> > feature electromagnetic interactions?
> >> >>
> >> >> It's not entirely clear to me what you mean by "effect through",
> >> > "express",
> >> >> and "feature" here, but I would say yes.
> >> >
> >> > Again, much as in points 1 and 2 above, I am implying that I expect
> >> > that
> >> > mass is formed through (consists of, expresses or features - in
effect,
> >> > mass
> >> > consists of- -features- -expresses- -effects through) electromagnetic
> >> > interactions. Or at least that electromagnetic interactions are
factors
> >> > expressing in mass - or giving rise to mass.
> >> >
> >> > However, you seem to be saying "yes": "mass [] does not effect
through
> > []
> >> > electromagnetic interactions" (regardless of level).
> >>
> >> As properties of elementary particles, electric charge
> >> and mass are orthogonal.. However, the field (electric,
> >> magnetic, nuclear, ect) surrounding a particle contains
> >> energy, E, and therefore, the field has mass, m,
> >> according to E = m c^2. Since the field is at rest
> >> WRT the point charge, the mass of the field gravitates
> >> according to it's mass-energy.
> >>
> >> Because the electron is considered to be elementary,
> >> it can have no structure. The electron's electric charge
> >> resides at a point. The energy of the electric field
> >> generated by that point charge contributes to a portion
> >> of the electrons observed mass.
> >>
> >> quarks are also elementary point particles that carry
> >> fields corresponding to both the electric and nuclear
> >> forces. The energy of each field contributes to the
> >> observed quark mass. The quark's mass is much
> >> greater than that of an electron's because the energy
> >> contained in the quark's nuclear field is much greater
> >> than that of its electric field.
> >
> > Ok, thank you. I may have a vague understanding of what you are saying.
If
> > I
> > may still go on, I speculatively propose for consideration, although it
> > may
> > seem a repeat of what you said above, that such fields - such
mass-fields
> > and compounds of them - are the force which is called "gravity".
>
> No "mass fields". Mass is a scalar. An electric field
> possesses magnitude and direction as a function of
> location in space and is represented by a vector.
So, no more hair-brained concoctions:
Essentially, my theory is that, a field, (force) F, in interaction with
other bodies - planets or galaxies - consists of mass and direction; the sum
of the mass force and direction force of a field is the gravitational force,
G, which it acts upon other bodies. Perhaps that would be represented more
as mass (sitting there energy) plus energy with direction, GF = MF + VF.
This implicitly probably discounts the concept of "inertia". Also, it does
not attempt to express the force of energy of the forces - your work
probably takes care of that.
>
> Suppose that, at a given location in space, there is an
> electric field represented by the vector, E. That electric
> field is generated by a point charge located elsewhere in
> space.
Those two statements are probably the two that I can least conceptualise -
electric field generated by point charge located elsewhere?
>
> The energy density (Joules / meter^3), a scalar, at the
> point of interest is proportional to the square of the
> electric field strength, E^2. The mass density (Kg /
> meter^3), also a scalar, is proportional to E^2 / c^2,
> where c^2 is the speed of light squared.
>
> Now, center a small sphere of volume, V (meter^3), on
> the point of interest. The mass, m, within that small
> sphere is then proportional to the energy density and
> to the volume of the sphere:
>
> m ~ V * (E / c)^2
>
> A gravitational force field (a vector) emanates from that
> small spherical volume in all directions. If you are a
> distance, R, away from the sphere, due to gravitational
> attraction, you'll be accelerated towards the sphere with
> an acceleration, g, that's proportional to the mass, m,
> contained within the sphere, and inversely proportional
> to the square of the distance, R:
>
> g = m * G / R^2 ~ [ V * (E / c)^2 ] * G / R^2
>
> Where, G, is the universal gravitational constant .
This seems to presume that I am "distance, R, away from the sphere" _and
inertial_. I am exploring the possibility that instead of that model perhaps
it is more a case of me as GF = MF + VF (and discounting the distance, R,
factor) in relationship with, if the above does not need alteration, m * G /
R^2 ~ [ V * (E / c)^2 ] * G / R^2.
Essentially, gravity expresses through causing different forces to cohere
with each other.
>
> So, due to the mass-energy density within a small
> spherical volume element, wherein the electric field
> strength is E, there will be a gravitational force on
> you (towards the sphere that's proportional to the
> square of the electric field strength, E^2, and that is
> inversely proportional to the square of your distance,
> R^2.
>
> That's the gravitational force from one small volume
> element. To get the toal gravitational force on you,
> you have to sum-up all the little forces (direction and
> magnitude) from a multitude of little adjacent spheres
> that cover all of space where the electric field is finite.
>
> Of course, you are in the electric field, and you would
> feel the many orders of magnitude stronger direct
> electrostatic force of that electric field if your body
> possessed even a minute static electric charge (like
> Tesla your hair might standup on end).
>
> You may ask questions about this, but please, let's not
> have any more hair-brained concoctions. OK ?
>
> [old Man]
>
> > There are
> > various, shall we say, degrees of force of fields (- effectively, mass).
> > Any
> > such field is obliged to reside at the, shall we say, degree which its
> > force - its mass-field - expresses. (For example, gas, water, rock
reside
> > according to their "degrees of force of fields" or mass-fields, which
also
> > includes their velocities, in interaction with each other).
> >
> > In effect, "Gravity" (of- -between masses) may be a density multiplied
by
> > velocity forces relationship.
> >
> >
> > Perhaps there is nothing original here - unless that there is a lesser
or
> > different sense of "pull" and more of " field relationship effect", but
> > with the fields, at some level of [force], interacting.
-- Peter Kinane http://www.effectuationism.com
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