Re: Inelastic Light Scattering?
mmeron_at_cars3.uchicago.edu
Date: 01/19/05
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Date: Wed, 19 Jan 2005 05:34:53 GMT
In article <cskef7$3m4$5@rainier.uits.indiana.edu>, glhansen@steel.ucs.indiana.edu (Gregory L. Hansen) writes:
>In article <Pine.LNX.4.50.0501191139190.9780-100000@localhost>,
>Timo Nieminen <timo@physics.uq.edu.au> wrote:
>>On Wed, 19 Jan 2005, Gregory L. Hansen wrote:
>>
>>> Uncle Al <UncleAl0@hate.spam.net> wrote:
>>> >"Gregory L. Hansen" wrote:
>>> >>
>>> >> I'd read about inelastic x-ray and neutron scattering, and it occured to
>>> >> me that the same should be true of visible light. Visible light hitting
>>> >> some arbitrary shiny surface should have some photon-phonon interactions.
>>> >> But I don't recall seeing that discussed in any of the textbooks. Seems
>>> >> like it could be a probe of material properties.
>>> >
>>> >Impinging circularly polarrized light on a surface imparts angular
>>> >momentum. Classic experiment.
>>>
>>> Ellipsometry?
>>>
>>> I know of methods involving reflectance or transmission versus angle or
>>> frequency. But I was thinking of a change in frequency, say 600 nm going
>>> in and 620 nm coming out. I don't think I've seen anything like that in
>>> visible light.
>>
>>Which reminds me, technically we use a kind of inelastic scattering to
>>measure rotation frequencies of optically spun microparticles. The two
>>circular basis polarisation components are frequency shifted in opposite
>>directions by the particle rotation, and we measure the beats. Of course,
>>the change in frequency is very, very small compared to the optical
>>frequency.
>
>Beats, that's clever. I knew about Doppler shifting, but measuring a beat
>frequency has to be a lot more sensitive than measuring two wavelengths.
>
Of course. That's what the cops are using (radar gun).
Mati Meron | "When you argue with a fool,
meron@cars.uchicago.edu | chances are he is doing just the same"
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