Re: Coulomb's constant is a CGS kludge
From: FrediFizzx (fredifizzx_at_hotmail.com)
Date: 02/25/05
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Date: Fri, 25 Feb 2005 00:07:54 -0800
"Eugene S." <user@host.com> wrote in message
news:NXxTd.12073$VD5.3575@twister.socal.rr.com...
|
| "John C. Polasek" <jpolasek@cfl.rr.com> wrote in message
| news:gt8t11p0bugm5jpv6itnuia6t4ufq8jr26@4ax.com...
| > On Fri, 25 Feb 2005 03:22:58 GMT, "Eugene S." <user@host.com> wrote:
| >
| > >You got it all backwards.
| > >
| > >In cgs we start with Coulomb law
| >
| > No, Coulombs law is defined as force F
|
| Coulomb's law says that force is proportional to product of charges,
| divided by square of distance between them. Electric field is defined as
| force acting on a unit charge.
|
| >
| > > and define a unit of charge so that
| > >E = Q/4pi*r^2 in vacuum.
|
| Actually, I stand corrected, it should be just Q/r^2.
|
| >
| > Then E must be coulombs per meter^2, divide it out. And that doesn't
| > make sense. It needs to be a forcing function in volts per meter. See,
| > we are already losing grip with reality.
|
| Not coulombs per meter^2, but cgs charge units per cm^2.
| Volt is an artificial unit, it has no room in cgs. So is coulomb.
|
| >
| > >D is secondary to E and represents the
| > >electric field, corrected for the polarization of the matter.
| > >D = E + 4*pi*P;
| >
| > Then D is also coulombs/m^2. That's OK.
|
| units cgs per cm^2. Incidentally, so are E and H, but let's not go into
that
| yet.
|
| >
| > >in case of isotropic dielectric, P ~ E, D ~ E.
| > > In vacuum, E=D, because there is no polarization.
| >
| > Vacuum does polarize, vacuum capacitors are proof of that.
|
| By 'polarization' we mean that there are electric charges in the
dielectric,
| they get displaced by an external electric field and, as a result, they
| create
| secondary electric field. Total electric field inside the dielectric is
| equal to
| external field plus field created by polarized charges. In the vacuum
there
| are no charges -> no polarization.
|
| Vacuum capacitors work simply because there is electric field in the
vacuum,
| it has nothing to do with polarization.
ROTFLMAO! Did you ever study particle physics?
FrediFizzx
http://www.vacuum-physics.com/QVC/quantum_vacuum_charge.pdf
or postscript
http://www.vacuum-physics.com/QVC/quantum_vacuum_charge.ps
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