Re: The Complete Disproof of Relativity and current Quantum Mechanics

From: Jeff (JLeeCforRP_at_aol.com)
Date: 02/04/05 

Date: 3 Feb 2005 18:41:58 -0800

Franz wrote:

"You are totally out of date"

Jeff, reply:

FACT: I can, using Reality Physics (as I show on my website) calculate
the exact wavelengths of the Bohr Hydrogen atom using the de Broglie
Equation. Now, since you are so "up to date", let's see you do it with
the de Broglie Equation as it is presently understood current QM.

You say the Bohr Hydrogen Atom is "out of date" as understood by
current QM. Of course it is, since QM can't find a way to use the de
Broglie Equation to describe it, they scapped it. Well, I just brought
it back, and in doing so, completely killed QM. But forget the Bohr
atom. How do you explain the fact (as also shown on my website) that I
can also exactly calculate the wavelength of a photon emitted from an
electron as it jumps orbits using the de Broglie Equation of Reality
Physics. The frequency and wavelength of these photons eminating from
the atom can be measured very precisely by observational experiment,
and have nothing at all to do with the Bohr atom. So Bohr atom, or not,
I have corrected the de Broglie Equation to exactly calculate the
values of these photons as observed from experiment, and it works for
every electron jump in the atom. You can try it yourself if you don't
believe me and you will see I am right.

Now to the question as to: Why a photon, eminating from an orbiting
electron traveling at a velocity more than a hunderd times less than
the speed of light, can instantly travel at the speed of light?

The answer: "that the photon has no mass" is correct for your level of
thinking, and for the rest of those now involved in current QM.
However, using Reality Physics I will now give you the REAL reason: The
photon leaves the atom at "c" because the electron it was emitted from
is composed of "spinning light" to begin with, i.e., "the angular
momentum of photon spin". As the electron jumps energy levels it
"throws off" part of its photon spin as a photon, exactly equal to the
difference in energy levels. Since you are still "stuck" in current QM,
I really don't expect you to accept this, but it is easy to prove using
Reality Physics. (I don't have time to do it now but it is in my book.)

Pissed off because I correctly answered you question?

But you are right about one thing, I am not a very successful bluffer.
As a matter of fact, I am not a "bluffer" at all. I am a "Reality
Physicist" with the CORRECT answers.

I find that you, however, since you made the statement that you know
more about QM than I, are possibly one of the best "bluffers" I have
ever seen.

all the best,

Jeff Lee CENTER FOR REALITY PHYSICS
>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>

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