Re: scale-free complexity may be wrong: CUNY

From: Androcles (Androcles_at_)
Date: 02/07/05 

Date: Mon, 07 Feb 2005 23:00:56 GMT

"Daryl McCullough" <stevendaryl3016@yahoo.com> wrote in message
news:cu8fik02qkg@drn.newsguy.com...
> Androcles says...
>
>>> Just about everyone is. On the other hand, to believe that one
>>> is better at physics than Einstein, and Feynmann, and Hawking,
>>> and GellMann, and Weinberg is *supremely* arrogant. And foolish,
>>> when it comes from someone who can't even understand the algebra
>>> of special relativity
>>
>>If the cap fits, wear it, McCullough.
>
> You talk about foolish arrogance, and then you claim to understood
> physics better than people who win Nobel prizes in physics.

It wasn't a Nobel prize in mathematics, now was it?

> That is
> the sign of a loony, Androcles. There is no better definition of
> foolish arrogance.

What are the five stages of grief, now that your dearly beloved
relativity is dead?

1. BARGAINING ---
     Oh please, Androcles, try to learn physics, you know I'm smarter
than you.

2. ANGER ---
Tell Androcles what a looney he is. (Actually, he's just the
pathologist conducting the post-mortem, relativity was still-born).
This is the stage McCullough is in now.

3. DENIAL ---
      Einstein didn't define time SUCH THAT (16+4) / 2 = 16
      in his equation
½[tau(0,0,0,t)+tau(0,0,0,t+x'/(c-v)+x'/(c+v))] = tau(x',0,0,t+x'/(c-v))
SUCH THAT
½[tau(0,0,0,t)+tau(0,0,0,t+16+4)] = tau(x',0,0,t+16)

4. DEPRESSION ---
(Androcles doesn't give a ***, so no comment.) See a
psychotherapist.

5. ACCEPTANCE ---
       (McCullough isn't at this stage yet)

>
>>Tell us, what IS the function tau() such that
>>½[tau(0,0,0,t)+tau(0,0,0,t+x'/(c-v)+x'/(c+v))] =
>>tau(x',0,0,t+x'/(c-v))
>
> Use the Lorentz transformations:
>
> t' = gamma (t - vx/c^2)
> x' = gamma (x - vt)
>
> (y and z are unimportant for the problem at hand)

We can't, old son, we are still TRYING to DERIVE them FROM the
equation
½[tau(0,0,0,t)+tau(0,0,0,t+x'/(c-v)+x'/(c+v))] = tau(x',0,0,t+x'/(c-v))
and they do not yet exist.
Look up "a priori" in a dictionary :-)

>
> Let Sam and Joe be at rest relative to each other. Let e_1 be
> the event at which Sam sends a light signal to Joe, and let
> e_2 be the event at which Joe receives the signal and bounces
> it back towards Sam, and let e_3 be the event at which Sam
> receives the return signal.
>
> Let's use the following numbers: Suppose that there is a frame
> in which Sam is moving towards Joe at 3/5 the speed of light.
> (Which means that gamma = 1.25)
> Let the distance between Sam and Joe be 6.4 light-seconds in this
> frame. Assume that e_1 is the origin (x=0, t=0)
>
> Then the coordinates of e_2 is given by the following equations:
>
> 1. x_2 = c t_2 (position of light signal at time t_2)
> 2. x_2 = v t_2 + L (position of Joe at time t_2)
> = 3/5 c t_2 + 6.4
> 3. x_3 = x_2 - c (t_3 - t_2) (position of light signal at time
> t_3)
> 4. x_3 = v t_3 (position of Sam at time t_3)
> = 3/5 c t_3
>
> Solving for x_2, x_3, t_2, t_3 gives
>
> x_1 = 0
> t_1 = 0
>
> t_2 = 16 seconds
> x_2 = 16 light-seconds
>
> t_3 = 20 seconds
> x_3 = 12 light-seconds
>
> Okay. Now plug these results into the equations for x' and t' to
> find the coordinates in Joe and Sam's frame:
>
> t_1' = 0
> x_1' = 0
>
> t_2' = gamma (t_2 - v/c^2 x_2)
> = 1.25 (16 - 3/5 * 16)
> = 8 seconds
> x_2' = gamma (x_2 - v t_2)
> = 1.25 (16 - 3/5 * 16)
> = 8 light-seconds
>
> t_3' = gamma (t_3 - v/c^2 x_3)
> = 1.25 (20 - 3/5 * 12)
> = 16
>
> x_3' = gamma (x_3 - v t_3)
> = 1.25 (12 - 3/5 * 20)
> = 0
>
> So, you can see perfectly well that t_2' = 1/2 (t_3' - t_1').

Yes, of course. Well done. So the speed of mosquitoes
is 5 fps in all frames of reference, as you have now proven, and
the distance between Sam and Joe is 40 ft when they stop at
a red light and shrinks to 32 ft when they move at 3 fps.
Better tell the world of this important discovery, McCullough.
Ever wondered what would happen if the mosquito flew from
Joe to Sam and back to Joe again?
Why, we'd have
 [tau(32,0,0,0) + tau( 32,0,0,20) ] / 2 = tau(0,0,0,4)

and (16 + 4)/2 = 4 instead.

Androcles.