Re: Time Dilation Model, NO ONE can point out what's wrong
guskz_at_hotmail.com
Date: 02/08/05
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Date: 8 Feb 2005 00:10:49 -0800
Jesse Mazer wrote:
> guskz@hotmail.com wrote:
>
> >There are but a few simple lines (5 sentences) below until a
Conclusion
> >is reached.
> >
> >Someone must clearly specify the first line he reads that is
incorrect
> >and why.....if no error is wrong than there remains insufficient
> >evidence of time dilation (outside the muons experiment).
> >
> >
> >Setting:
> >
> >We will call 2 platforms: A & B
> >
> >A goes 10km/s and B goes 40km/s in relation to Earth (difference =
> >30km/s)
> >
> >Now if Earth disappeared, the only thing A would observe is that B
is
> >30km/s faster and likewise B would observe A moving 30km/s.
> >
>
>--------------------------------------------------------------------------
> >
> >Symptom:
> >
> >Relativity's Law specifies there is no Universal Absolute Reference
> >Frame (everything is relative), so by this law it is irrelevant to
Time
> >Dilation wether A must *accelerate* or *decelerate* to reach same
> >velocity as B.
> >
> >This same symptom also applies to B if it wishes to reach A's
velocity.
> >
>
>-------------------------------------------------------------------------
> >
> >Conclusion:
> >
> >By the symptoms provide above, it is impossible for A or B to age
> >differently than the other and therefore there cannot be any Time
> >Dilation.
> >
>
> What do you mean by "age differently"?
That's what was written...very few lines and people still make reading
errors.
It says: "it is impossible....to age differently"
> As long as both continue to move
> at a constant velocity relative to another, relativity says there is
no
> absolute truth about who is aging slower--B is aging slower in A's
> reference frame, and A is aging slower in B's reference frame.
>
Correct, that's what was written.
> >
> >Likewise, it is impossible for a twin to leave A, until he reaches
the
> >same velocity as B and then accumulate an age difference *depending*
on
> >how long he remains at the same velocity as B (also the same if twin
is
> >leaving B and going to A).
> >
>
> If two twins on platform A start out at rest to each other and the
same
> age, then one twin changes velocity until his velocity matches that
of
> platform B,
You used the Correct words: "changes velocity" instead of "accelerate
or decelerate" for that's the foundation of Relativity, meaning there
is no Absolute Frame of Reference.
>.....then in platform A's frame the twin who changed velocity is
> aging slower, and in platform B's frame the twin who remained on
> platform A is aging slower.
That is not what was written which is that there is ALSO another twins
on platform B..
... and the remaining brother on platform B is NOW also arguing with
the new traveler from platform A that his twin is aging less then them.
> But in order for them to actually compare
> ages at a single location, one of them will have to change velocities
> again, and this will break the symmetry, so both frames will make the
> same prediction about who has aged less when they meet again.
>
> Jesse
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