Re: 2 Questiosn On Parallel Plates ?
From: John C. Polasek (jpolasek_at_cfl.rr.com)
Date: 02/28/05
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Date: Mon, 28 Feb 2005 09:25:51 -0500
On Mon, 28 Feb 2005 08:53:27 GMT, "Pib" <Pib@NugPib.com> wrote:
>1. parallel plate with capacitor of 20uF, plate is 0.5mm apart.
>
>Find
>1. Area of each plate
>2. potential difference if there's a change of magnitude of 30uC on each plate.
>3. stored energy
>4. electric field between the two plates
>5. charge density on the plate.
>
> _ _
> |_| |_|
> |_____|
> .5mm
>
>I know C=Eo*A / d
>
>so would A=Eo*C/ D or A=Q / Eo *E
>
>A= (8.85*10^ -12 ) * 20 / (.5 * 10^ -3) ?
>
>
>2. three point charges on the x axis q1= (10uc) at x= -4m, q2= (-5uC) at the origin, q3= (-20uC) at x= 4m.
>
>
>Q1(-4,0) Q2(0,0) Q3(4,0)
>(+)----------(-)-----------(-)
>10uC -5uC -20UC
>
>
>Find
>1. electric field at origin
>2. force on q2
>
>
>would electric field on orgin = Zero or would it be F1= Ke |q1|q2| / r^2 & F2= Ke |q3| |q2| / r^2
>
>F1= (8.99* 10^9) (10 * 10^ -6) * ( 5*10^-6) / (-4)^ 2
>
>F2= (8.99* 10^9) (20 * 10^ -6) * (5*10^-6) / (-4)^ 2
>
>what would i do after this ? x & y components ?
>
>
>
>
>
>
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I'll answer #1, and you can take it from there. The plate area is
12,150m^2 or 0.2789 acres.
Does this help? I assume vacuum or air dielectric.
Mr. Dual Space
If you have something to say, write an equation.
If you have nothing to say, write an essay
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