Re: Relativity question

From: RP (no_mail_no_spam_at_yahoo.com)
Date: 03/24/05 

Date: Wed, 23 Mar 2005 23:02:08 -0600

bz wrote:

> RP <no_mail_no_spam@yahoo.com> wrote in news:3aeihpF6a5rd6U1
> @individual.net:
>
>
>>in many vacuum tubes the electron beam
>>is accompanied by a reverse flow of positive ions,
>
>
> When vacuum tubes get gassy, it is time to replace them.
>
> You can tell when a vacuum tube is gassy. The positive ions GLOW because
> they collide with the electrons, are excited and emit photons.
>
> Also the current increases dramatically. Grids become less effective at
> controlling the plate current, signal output decreases, efficiency
> decreases, Waste heat increases. Screen grid current flow goes up and can
> damage the screen grid. The plate heats. Under extreme conditions, holes
> can melt in the plate or the tube's glass envelope can soften and sag or
> even puncture.
>
> Ions impacting on the cathode cause it to overheat and damage the
> thermionic coating on the cathode.
>
> In short, gassy tubes (unless they are voltage regulators, thyratrons or
> mercury vapor rectifiers) are bad tubes. Gassy vacuum tubes are bad vacuum
> tubes.

A perfect vacuum isn't even theoretically possible; there will be some
gas present. Because of this there will be a magnetic field external
to the tube generated by a counter-flow of electrons and positive
ions. This needs to be properly accounted for when attempting to test
for a magnetic field external to the tube. To wit, any magnetic field
measured will be a direct indication of the presence of a counter-flow
of positive charges. The proof of my prediction that a monopolar beam
will generate no magnetic field, will then lie in the fact that the
magnetic field detected doesn't correspond correctly to the magnitude
of the electron current present, but rather to an electron current
that is equal and opposite to the much smaller positive current present.

The real question is, supposing it exists, how are you going to detect
the magnetic field of the beam? You have to take into consideration
not only the above complication, but the electrostatic inductive
force, which will overwhelm any classically predicted magnetic field
generated by the beam, and as well you need to know what predictions
my equations make. When you have motion of a point charge external to
the beam the force will always act along the line joining the charges,
but it won't be symmetrical wrt the beam, since the angle of motion of
the charges wrt each other is a tremendously big factor in determining
the magnitude of the force. For the two halves of the beam that the
external charge sees from the perpendicular, the forces produced by
these two halves will be equal only when the external charge is moving
parallel or anti-parallel to the beam. It will be extremely difficult
to make a determination as to whether it is a magnetic field producing
the effects, or the generalized em field that I propose.

You will need to track the paths of free electrons moving wrt to the
beam with a precision that may not even be possible for several
decades or even centuries, that is, unless my model is adopted based
upon the *existing* data, and technology gets a boost in the right
direction :)

Again, I'll state that the existing empirical data already supports my
contentions. In the frame of the beam's electrons there is no current,
this is elementary, and thus there can be no magnetic field in that
frame and thus nothing to counter the Coulomb force. When you consider
a conductor, OTOH, regardless of your motion wrt the conductor you
will experience a magnetic field, and the reason for this is that you
cannot be in the frame of both the electrons and the protons
simultaneously. The vector sum of the forces of these two monopolar
currents on an external point charge corresponds to the classical
magnetic field. This is derived in my little essay on the subject in
no uncertain terms.

Richard Perry

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