Re: Wave as wave, particle as particle
- From: "PD" <pdraper@xxxxxxxxx>
- Date: 3 May 2005 11:53:29 -0700
RP wrote:
> PD wrote:
> > RP wrote:
> >
> >>zhayne wrote:
> >>
> >>>RP wrote:
> >>>
> >>>
> >>>>zhayne wrote:
> >>
> >>>Hey. RP. Explain in a nutshell how the phosphors can still
> >>>get a hit in a one at a time "photon" emission double slit
> >>>experiment.
> >>
> >>You, as is also true of most people, laymen and physicists alike,
> >
> > aren't
> >
> >>aware of the actual details of such experiments.
> >>When photon numbers are counted each emission or transition event
is
> >>merely *assumed* to be caused by one photon, the number of events
> >
> > then
> >
> >>counted and assumed to equal the number of photons. Logic doesn't
get
> >
> >
> >>any more circular than that!
> >>There is no way to count the photons emitted from the source in
such
> >
> > a
> >
> >>manner, moreover every bit of matter in the equipment as well as in
> >
> > the
> >
> >>surrounding walls are emitting light in a continuous spectrum. In
> >>experiments that intend to measure interference effects, such as in
> >
> > the
> >
> >>double slit experiment, you are measuring interference of light and
> >
> > thus
> >
> >>the properties of light called phase and/or polarity, I see no
> >
> > integer
> >
> >>numbers associated with those qualities, only angles.
> >
> >
> > In a case where there is only a source and a photosensitive counter
> > array(no intervening slits), I can count the rate at which hits
appear
> > on the counter array.
> >
> > Now insert a pair of slits or a grating, and multiply times the
> > fraction of the area that is transparent through the insertion to
get
> > an expected hit rate. This will indeed be the hit rate as seen on
the
> > counter array, determined completely by geometric aperture.
However, in
> > addition, the hits will strike the counter array in a pattern
predicted
> > by wave interference.
> >
> > I can think of no natural "conspiracy" that would explain why the
hit
> > rate in the latter case would be identical to what you would expect
> > from a photon model and yet not be from photons.
> >
> > PD
>
> And why wouldn't classical waves and conservation of energy produce
the
> same result? And if you cannot counter this, then doesn't the same
> logical argument that you provided above apply to the classical
model?
> Petitio principii.
>
> Richard Perry
Indeed, interference is a wave phenomenon. This, however, does not rule
out interference due to the wave aspect of light, even when the
intensity is low enough that the light comes one quantum (photon) at a
time.
I made no claim that it was anything different. I was quibbling with
your claim that photons cannot be real or consistent with this picture.
PD
.
- References:
- Wave as wave, particle as particle
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