Re: How long is a photon?
- From: "Ken S. Tucker" <dynamics@xxxxxxxxxxxx>
- Date: 15 May 2005 13:13:52 -0700
FrediFizzx wrote:
> "Ken S. Tucker" <dynamics@xxxxxxxxxxxx> wrote in message
> news:1116109859.271322.163890@xxxxxxxxxxxxxxxxxxxxxxxxxxxxxxx
> | Read Fredi's post and the papers, ther're sophisticated,
> | and not questioning Fredi's analysis, but instead asking
> | a question about photons.
> |
> | Probably easier if I put it into a form of a theory...
> |
> | Postulate:
> | Let "h" be a quantum of Action, then h/t (t=time) be a
> | Rate of Action, i.e quantums per seconds.
> |
> | Let frequency "f" be expressed as "1/t" then, the
> |
> | Rate of Action = h/t = h*f = Energy.
> |
> | Let me do a diagram, where "a"'s are units of
> | action, and demo two distinct frequency's,
> | (dot's represent wavelength),
> |
> | 1) a......a......a......a
> |
> | 2) a...a...a...a
> |
> | Where the energy of (2) = 2* energy of (1) where
> | I postulated the photon energy = rate of action above.
> |
> | It follows a photon consists of at least two succesive
> | actions in order to establish an action rate, which is
> | equivalent to energy.
> |
> | Does that make sense?
>
> Are you trying to link this to our two wavelengths long?
Would maybe be an acceptable answer???
> If so, then we
> need 1/2 actions for the "a's" so that the full two wavelengths = one
h?
> Hmm... Where have I seen this h/2 before? ;-)
Ok, trying get a sense of basics of the floton.
> | Check it out this way, I'll use Planck's h =
> | 6.6..*10^-27 ergs*secs == Energy*Time.
> |
> | Take the partial diff of "h" wrt Time and find
> |
> | &h/&Time = Energy.
> |
> | In words, that equation means: A constant Energy
> | of light is shining on you, and that constant has
> | a constant change of action "h" over "Time", somewhat
> | like getting a sun-tan.
> |
> | The partial derivative above often throws people but
> | (IMHO) it's quite simple. Let me provide an example:
> |
> | Two drunk fishermen are sitting in a boat,(me and Fredi).
> | One claims *everything else being equal* says fish bite
> | in a rain. The other claims *everthing else being equal*
> | they bite better when it's sunny.
> |
> | The point being, we vary only the weather variable, by
> | stating *everything else being equal*, so all those
> | potential variables are - for the sake of argument -
> | held constant, that's what *partial differentiation*
> | does, it defines how Freddi and Ken can argue about
> | how the fish bite as the weather varies.
> |
> | Applying that to this equation,
> |
> | &h/&Time = Energy,
> |
> | assumes Energy is constant, but we still have
> | a Rate of change of Action.
> |
> | >From what I ascertain by study of *Action* is an
> | enigmatic unit. Planck, Weyl and Einstein studied
> | it carefully, so I recommend the same. Seems it's
> | a fundamental invariant.
>
> Yes, of course. We look at it this way. If it were possible to see
> this two wavelengths long photon's energy density coming at you head
on,
> you would see a 4pi rotation of the E vector. But each wavelength is
> only a 2pi rotation.
> FrediFizzx
I'm considering a floton to be spin 0 and a photon
to be spin 1. We do know the photon spin 1 by studying
it's reactions with matter, but I wonder if we looked
only at the electron when an atom emits a photon.
Anyway probably a dead end, but needs to be eliminated
to get GR solution.
Regards
Ken
.
- References:
- How long is a photon?
- From: dlham
- Re: How long is a photon?
- From: FrediFizzx
- Re: How long is a photon?
- From: Ken S. Tucker
- Re: How long is a photon?
- From: FrediFizzx
- How long is a photon?
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