Re: Will Radio Engineering be QM's worst nightmare?

Greg Neill wrote:
> > No no, I have interrupt you there because I said place the wire *in
> > between* the 100K & 1 ohm resister.
>
> That's ambiguous. "Between" most readily implies in series with,
> between the two.

Again, there are two resisters-- 100K and 1 ohm. The two R's are in
series. The 1 ohm end goes to ground and 100K end goes to output of
amplifier. One end of the 2" wire goes in between the 100K and 1 ohm
resisters.



> > By placing the antenna in
> > between both resisters you are looking across the 1 ohm.

Bingo!


> So guess what ... the voltage across the 1 ohm is 1 ohm * 9.9999 uA = 9.9999 uV

Bingo! LOL


> So your circuit is:
>
> 100K
> Osc. out O-----/\/\/\/----+----+
> | |
> | \
> wire | / 1 Ohm
> | \
> | |
> GND O----------------+----+

No, there's a 9.9999 uV ac potential between the 100K and 1 ohm R. You
don't need to short the 1 ohm R with a 2" wire. :-) It's an open wire
just like a yagi antenna. If you want to get into technicalities then
you'll get better response if you connect the middle part of the 2"
wire to the 100K & 1 ohm R. A 1 element yagi usually has the source in
the middle of the element unless you want to put it at the end and get
a wider bandwidth spread.


> > > , but if you can determine the inductance of 2" of wire you can calculate its voltage.
> >
> > I already know it, 4.77 + j 1231. Since that is far higher than 1 ohm
> > then it's no problemo.
>
> Using my values, and assuming a model for the wire that consists of
> its resistance in series with the parallel combination of the
> inductance and capacitance:
> +---[I]---+
> | |
> ----[R]----+ +-----
> | |
> +---[C]---+
>
> then I get an impedance of (0.35 + 310j) Ohms.

Again, you were think that I wanted to short the 1 ohm resister with
the 2" wire. Not sure why you thought that but no biggy. Do you get
it now?

.

Relevant Pages

  • Re: Simple Question
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