Feynman Vol. 3 Chapter 5 Question
- From: "jss7776@xxxxxxxxxxx" <jss7776@xxxxxxxxxxx>
- Date: 21 Jul 2005 11:45:58 -0700
I have a question for anyone who has read Feynman Vol. 3 Chapter 5.
He discusses the base states (+S,0s,-S,+T,0T,-T etc.) He then talked
about
the probability amplitude of a particle going from going from one state
to another in the form of <final state|initial state>. So, he gives the
ampitude of going from say +S to -S as <-S|+S>. He then uses the short
hand of i,k representing the state of the filter refered to such as
1~+S ect. He makes the statement that <j|i>=0. Looking at, for
example, equation 5.15 this appears not to be true. Here the particle
starts in the +S state and goes to the -S state. This could be written
as <-S|+S>. Couldn't this be written as <j|i>=not zero? Does the
notation <j|i> mean going from i to j state without passing through
another filter? In 5.30 the particle goes through appartus A and it is
written <j|A|i>.
.
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