Difficult integral - who can help?
- From: mark@xxxxxxxxxxxxxxx
- Date: 22 Jul 2005 03:29:33 -0700
Hello together,
[I posted this already on sci.math, but perhaps you are more familier
with this type of problem. So sorry for cross-posting,. but the problem
is quiet urgent :-( ]
]
During my calculations for a physical problem I derived the following
integral that must be solved:
Integral[z]:=
\int_{-\infinity}^{z} dz' Exp[-i \pi (z'^2 - i \alpha z')] *
\int_{-\infinity}^{z'} dz'' Exp[+i \pi (z''^2 - i \alpha z'')]
As you see its a double-integral.
Please note:
z is real
i = \sqrt(-1)
\alpha is real and also \alpha > 0
I solved the integral for z=\infinity. So I have Integral[\infinity]
which gives 1/2.
But I also need Integral[z]. I asked lots of people and tried some
tricks, but nothing worked for this integral.
Perhaps you can help.
Thanks a lot!!!
Bye,
Mark
.
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