Re: About EMR (kst)


TomGee wrote:
> Ken S. Tucker wrote:
> > IMHO, we should examine the basic circumstances
> > needed for photon emission (aka EMR), independant
> > of the frequency, which Doppler can adjust anyway.
> >
> >
> I agree, and in fact I have posted an alternative explanation which
> takes into consideration the needed basic circumatances, as you put it.
> >
> >
> > In Purcell's EM on pg 11, describes "Energy of a
> > System of Charges", he calls "electrical potential
> > energy", wherein the simplest case uses two charges,
> >
> > Work = q1*q2/R12 = P
> >
> > and then sums to assemblies.
> >
> > A photon derives energy from the "electrical potential
> > energy of a system"
> >
> >
> But how have you separated e from m if they are interdependent?
> Shouldn't you say "from the 'electrical and magnetic potential...."?

Yes, that's agreeable. I was trying to stay simple.
But you can get *sparks* from discharging a capacitor
or a coil, as you suggest :-).

> > so P becomes...
> >
> > P => p + energy(photon)
> >
> > where
> >
> > p = q1*q2/r12
> >
> > and p < P.
> >
> > The point I'll stress, photons (EMR) require a relative
> > change in the relation of q1 and q2 for emission.
> >
> >
> Yes, I agree.
> >
> >
> > An example is the relative change in an electron orbital,
> > w.r.t the nucleus.
> >
> > Maxwell's famous "displacement current" given by
> > the partial &E/&t really requires a charge "q1" to be
> > detected, like,
> >
> > q1*&E/&t = &(q1*E) /&t = &F/&t .
> >
> > But to complete the dipole the source of E should
> > use charge "q2", where q1 and q2 are different and
> > separate by some length R12=ct.
> >
> > Using Force*distance = energy "P" gives,
> >
> > P = F*R12
> >
> > so that,
> >
> > &P/&R12 = F
> >
> > which means the emission or detection of EMR
> > is relative, ie a single charge can't radiate and
> > therefore can't be affected by radiation.
> >
> >
> That sounds correct to me, Ken. My model requires a transformation
> from a stable state into a temporary active state for the creation of
> light. The em wave transfers energy into the "energy potential" photon
> particle and light is created from that interaction.

Regards
Ken

.

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