Re: If a PHoton has no electric charge how does it create the EM field ?


Ken S. Tucker wrote:
> gilheron wrote:
> > If a Photon has no electric charge how does it create the
> > ElectroMagnetic field ?
>
> A photon seems to consist of a (+) charge and
> a (-) charge, because "pair-production" is always
> possible since,
>
> Photon + photon => Positron + Electron + photon.
>
> (That converts energy to mass).
>
> Very simply an Electric field is really a relation like
>
> (-) =======>(+)
> E
>
> with E being an Electric Field vector.
>
> The magnetic part of the photon appears when
> the photon is measured (annilihated) in an
> antenna for example, as the E-field vector
> encounters stationary matter and induces a
> Magnetic Field at the speed of light.
>
> There does not seem to be any concensus of
> what a "flying" photon is between emission
> and absorption, but what happens at each of
> those events is moderatedly understood.
>
> Anyway it seems quite reasonable to consider
> a photon as a pair of charges.
>

No, it's not reasonable. First of all, decay products say *nothing*
about the composition of the parent, any more than a a muon is composed
of an electron and two neutrinos, any more than a pion is composed of a
muon and a neutrino, any more than a neutron is composed of a proton
and and electron and a neutrino. So the fact that pair production
happens from photons implies nothing about what a photon is made of.

Secondly, a charged dipole is completely experimentally distinguishable
from a photon, by virtue of field moments, by virtue of charge
distribution probes, and by virtue of interaction cross-sections with
charged objects.

Third, you obviously are ignoring the *coupled* electric and magnetic
field equations which give rise to electromagnetic energy propagating
through space at a speed of -- miracle! -- light. These say that
magnetic fields are not only end-effects.

PD

.

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