Re: If a PHoton has no electric charge how does it create the EM field ?
- From: glhansen@xxxxxxxxxxxxxxxxxxxxx (Gregory L. Hansen)
- Date: Wed, 10 Aug 2005 15:01:33 +0000 (UTC)
In article <1123650389.941840.126720@xxxxxxxxxxxxxxxxxxxxxxxxxxxx>,
Y.Porat <maporat@xxxxxxxxxx> wrote:
>the particle does not know what is called a particle!!
>so ????
>
>will that be a reason for us to 'close the shop' and go home??!!
>
>of course anything we say and write is a human artifact
>yet we suppose that some of it is accepted by our *common
>understanding*
>to be 'real'
>and other thins are accepted commonly to be imaginary
>and only a product of someones imagination
>so it is all a matter of conventions
>yet our efforts all along our life is to make as much as possible
>as wide conventions as possible!!
Yes. But some people seem to draw the line between "real" and "imaginary"
conventions at the theories they don't like. Momentum is "real", but
momentum eigenstates are "imaginary". Even though momentum eigenstates
describe the "real" effect of changing the momentum-- how can a math
abstraction change something real, unless they're both real or they're
both math abstractions?
Some people probably think a force expressed in the position
representation is more "real" than a force expressed in the momentum
representation, too.
V(r) = kqQ/r, r is position
V(p) = gqQ/p^2, p is momentum
Which is more "real"? It's the same thing! Different representations of
the same thing. The first is the Coulomb potential in a basis of position
eigenstates, the second is the Coulomb potential in a basis of momentum
eigenstates.
Oh, no! I just said "position eigenstates"! Does that mean position is
an imaginary mathematical abstraction?
--
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mind-boggling amounts of excrement when you least expect it. "
-- Gene Spafford, 1992
.
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