Re: (electron <~> planet) Re: Basic question about atoms



Ron Baker, Pluralitas! wrote:
> Why would/should they be equal? Show us how the numbers work out?

Well if the electron absorbed more than it emitted, such as from a
nuclear decay, it would jump away and be free of the proton. If it
emitted more than it absorbed, such as from a nuclear inverse decay, it
would continue deeper toward and into the nucleus, eventually lodging
into a proton with the energetic help of an antineutrino to shield it
from further excitations. When the electron and proton spiral into the
same place in an ideal vacuum, which should also ideally take an
infinite while to radiate away because the moment never decays to
nothing, then any further power one plugs in for an arbitrary
transition is looped shut because the pair are in equilibrium. Outside
of vacuum, the pair assumes a new equilibrium based on the background
temperature, and will fluctuate around the new moment. I wish I could
find any pages along this line of thought, but there's only Larmor
power which doesn't say anything about the absorbance or efficiency of
radiation absorbed by the electron.

> But isn't the 'illuminating background' basically the prevailing
> temperature (blackbody radiation)? Isn't the range of the 'illuminating
> background' continuous? Wouldn't the resulting 'orbitals' be continuous
> in radius or probable radius?

Each orbital is already roughly continuous, from the bound
proton-electron potential surface (not hupersurface) to the edge of
space. Nodes classically represent infinite energy surfaces, centred
on fulcra like libration points in orbit but repulsive. The electron
and its ghost twin with imaginary states trace out the wave shapes.
They react to continuum background radiation by extending the orbitals,
and to discrete key radiation by reshaping the orbitals. In an ideal
vacuum (a timeout void), I'd expect the electrons to be at the wave
maxima or potential minima of each orbital. All s orbitals touch down
and become a dot at the nucleus. All p orbitals align (get honed) and
fall linewise tunnelling through the s electrons until they cap the s
electrons in all axes. Most of the higher orbitals will do the same
but cap with greater freedom; their least-momentum suborbitals,
however, become rings and lines and fall that way. The greater orbital
angular momentum of the higher orbitals acts like a guroscope,
stablising the electron from tracing out round shapes. This is why the
higher their trend the thinner their wave bulbs or rings are; instead
of whirling around the nucleus like the s electrons, they bounce and
trend more like springs and planets. Because all atoms have extended
orbitals, the continuum radiation transmitted by the orbitals is
greatly and mostly in fase with that of the detectors, so they are not
found to participate in energetic transitions. The experiments and
theorems disproving hidden variables are invalidated by the fact that
the states of one observable particle are /nonassociative/ thanks to
its wave-mocking twin.

-Aut

.



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