Re: impact resistance


"Turman" <butylka@xxxxxxxxx> wrote in message
news:1131467103.025704.58170@xxxxxxxxxxxxxxxxxxxxxxxxxxxxxxx
> ok - it is clear.
> these considerations are true. but to understand how much is 25 G may
> be there is some example- e.g. if we throw a brick on a brick from 1
> meter then we have 25 G or something..

The acceleration is roughly equal to the ratio of the height of fall to the
stopping distance. So something dropped from 1 meter that stops in 1mm sees
about 1000g. If the ground doesn't deform then it contributes zero to the
stopping distance. If the case of your object can deform 5mm you can reduce
the g from a 1 meter fall to 1/0.005 = 200g.







.

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