Re: Derivative Products of Form (df/dx)(dg/dx) in Physics 2: Devroye's Inversion Generalization Theorem


"Pod Spores Chumbly" <invaild@xxxxxxxxxxx> wrote in message
news:43bebbc5$0$44088$892e7fe2@xxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxx
>
> "OsherD" <mdoctorow@xxxxxxxxxxx> wrote in message
> news:1136527873.047892.95080@xxxxxxxxxxxxxxxxxxxxxxxxxxxxxxx
>> >From Osher Doctorow mdoctorow@xxxxxxxxxxx
>>
>> Pod Chumbly typed:
>>
>>>The math is trivial, get on with it. What is so important about it's
>>>meaning?
>>
>> Chumbly appears to have fallen from the sky with no knowledge of my
>> prior postings,
>
> I am very grounded.
> Perhaps you can explain what (df/dx)(dg/dx) really means?

df/dx ... a very tiny change in f divided by a very tiny but non-zero change
in x.

If I travel 30 miles in one hour, what is my velocity?
If I travel 15 miles in 30 minutes, what is my velocity?
If I travel 0.5 miles in 1 minute, what is my velocity?
If I travel 2640 feet in 60 seconds, what is my velocity?
If I travel 44 feet in 1 second, what is my velocity?
If I travel 0.0044 feet in 1 millisecond, what is my velocity?
If I travel 0.0000044 feet in 1 microsecond, what is my velocity?

The answer to every question is 30 mph.
In the real world, I rarely travel 30 miles anyway, but I often
travel 9.2 miles to see my friend, taking 15 minutes to do so,
having to stop at traffic signals along the way and keeping to
the speed limit of 40 mph.



> If you are going to post theories on the internet, be prepared for
> comments on your errors.
> A good Lesson for You.

A good lesson for you is to learn basic mathematics and not be rude,
or you will not get far. I can afford to be rude, you little twerp, I need
furtherance in my life.
Der alte Hexenmeister.



.

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