Re: NIST and MIT Confirm that E= mc2
- From: "Hexenmeister" <vanquish@xxxxxxxxxxxx>
- Date: Mon, 16 Jan 2006 05:46:41 GMT
"Mike Jr." <n00spam@xxxxxxxxxxx> wrote in message
news:1137360511.741568.191770@xxxxxxxxxxxxxxxxxxxxxxxxxxxxxxx
Randy Poe wrote:
> The old Sorcerer wrote:
> > "Mike Jr." <n00spam@xxxxxxxxxxx> wrote in message
> > news:1137261766.146500.47270@xxxxxxxxxxxxxxxxxxxxxxxxxxxxxxx
> > >
> > > "Albert Einstein was correct in his prediction that E=mc2, according
> > > to
> > > scientists at the Commerce Department's National Institute of
> > > Standards and Technology (NIST) and the Massachusetts Institute of
> > > Technology (MIT) who conducted the most precise direct test ever of
> > > what is perhaps the most famous formula in science."
> > >
> > > http://www.physlink.com/News/051229Emc2Einstein.cfm
> > >
> > > --Mike Jr.
> >
> > Which is not E = mc²/sqrt(1-v²/c²) as Einstein predicted
>
> No? What do you think the difference between those numbers
> would be for this experiment?
Since v=0 quite a bit. :-)
To get E = mc² you have to start from E² = p²c² + m²c4 and put p =
0, which means that you have to put v = 0. The equation is only valid
when the m is not moving and therefore E² is only equal to m²c4, or E
= mc².
Nothing else to do on a Sunday?
--Mike Jr.
E² = p²c² + m²c4 ???? Where do you get that from?
Total energy = mc² + mv²/2
Total energy squared:
E² = (mc² + mv²/2)²
= m²c^4 + 2m²c²v²/2 [ + m²v^4/4]
= m²c^4 + m²c²v² [ + m²v^4/4]
Since p²= m²v² by definition of p = mv,
E² = m²c^4 + p²c² [ + m²v^4/4, to be forgotten]
+------------------+----------+
| mc² | mv²/2 |
| | |
| | |
| | |
| | |
| Area | Area |
| =m²c^4 | = p²c² |
| | ----- |
| | 2 |
| | |
| | |
+------------------+----------+
| |
| | .
| Area | Area =?
| = p²c² | .
| ---- |
| 2 | .
+------------------+ . . . . .+
The lower corner is missing so that they can divide by sqrt(1-v²/c²)
(gamma = 1/sqrt(1-v²/c²) ) and always get the answer they like to
fit the data.
It goes hand in glove with the relativist's lookup table:
gamma Desired velocity
1 0.000000000000000
10 0.994987437106620
100 0.999949998749938
1000 0.999999499999875
10000 0.999999995000000
100000 0.999999999950000
1000000 0.999999999999500
10000000 0.999999999999995
No matter what the energy is, there is always an unmeasured
v of 0.99xxxxx that matches the data within the limits of
experi- mental error, and why you can't disprove the theory from
anything you do with particles.
I'll have to do a web page on the energy square...
--
Der alte Hexenmeister ist:
Sorcerer Androcles Dumbledore, Headmaster, hogwarts.physics
school for zauberlehrlings.
"One muggle's magic is another sorcerer's engineering"
http://www.androcles01.pwp.blueyonder.co.uk/how_to_be_as_smart_as_einstein.htm
http://www.androcles01.pwp.blueyonder.co.uk/people_v_Baez.htm
http://www.androcles01.pwp.blueyonder.co.uk/sundials.htm
http://www.androcles01.pwp.blueyonder.co.uk/RR_C7/RelativityRevealed.htm
.
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