Is M6 isomorphic to our universe?



Consider the state quotients and their mappings to particles for the sets
defined below in Mirror Set section;

SE0/SH0 = 1/1=1 ... light
SE1/SH1 = 1/2 ... weak
SE2/SH2 = 2/4=1/2 ... weak
SE3/SH3 = 12/8=3/2 ... hadrons
SE4/SH4 = 288/16=18=2*3^2 ... leptons
SE5/SH5 = 34560/32=1080=2^3*3^3*5 ... ?
SE6/SH6 = 777600/64=12150=2*3^5*5^2 ... ?

1/2 is degenerate.
All sets are made of 5 objects {1,2,3,4,5} and their various combinations.
I put 3/2 in the middle since, like in music, the universe seems to be
balanced around hadrons.

Proposition: 1 is isomorphic to Circle Group U(1) therefore to light.
Proof: Open
Comments: 1/1=1 shows that the simplest cycle is that of 1.

Proposition: 1/2 is isomorphic to the quotient group U(1)/SU(2) therefore to
weak.
Proof: Open
Comments: 1/2=1/(1+1) shows the 2 to 1 aspect of weak force.

Proposition: 3/2 is isomorphic to the quotient group SU(3)/SU(2) therefore
to hadrons.
Proof: Open
Comments: 3/2 structure of hadrons is obvious.

Proposition: 18=2*3*3 stands for leptons.
Proof: Open
Comments: 18=2*3*3 is reflected in the periodic table clearly.

Proposition: All particles are made of 5 fields
{light,weak,strong,time,gravity}, and they in turn are made of light.
Proof: Open
Comments: 5=1+1+1+1+1 shows that it is all made of 1 packed in different
ways by mirrors.

Proposition: M6 is isomorphic to our universe.
Proof: Open
Comments: Maybe rather the quotient set Sum[En/Hn,n=0;6].

Mirror Set
----------

There are two types of mirrors;
Exclusive and inclusive.
Exclusive ceates breadth while inclusive creates depth.
Exponential Set is an exclusive mirror while H-Set is an inclusive mirror.
In a dynamic reflecting environment, mirroring would be a mixture of the
two.
Since E and H do not commute, they preserve past;
EH /= HE
A sequence of 'n' mixed reflections is a member of the ensemble;
Mn=(E+H)^n

ESet and HSet are special sets created by iterating the same mirroring.
They are related closely since they create unique sets.

Exponential Set;

E0=
E1=EE=E={,}={}
E2=EE1={,{}}
E3=EE2={,{},{,{}}}
E4=EE3={,{},{,{}},{,{},{,{}}}}
E5=EE4={,{},{,{}},{,{},{,{}}},{,{},{,{}},{,{},{,{}}}}}
E6=EE5={,{},{,{}},{,{},{,{}}},{,{},{,{}},{,{},{,{}}}},{,{},{,{}},{,{},{,{}}},{,{},{,{}},{,{},{,{}}}}}}

H-Set;

H0={}
H1=HH0={,{}}
H2=HH1={,{,{}}}
H3=HH2={,{,{,{}}}}
H4=HH3={,{,{,{,{}}}}}
H5=HH4={,{,{,{,{,{}}}}}}
H6=HH5={,{,{,{,{,{,{}}}}}}}

The number of states;

SE0=0!=1
SE1=1!0!=1
SE2=2!1!0!=2
SE3=3!2!1!0!=12
SE4=4!3!2!1!0!=288
SE5=5!4!3!2!1!0!=34560
SE6=6!5!4!3!2!1!0!=777600

SH0=2^0=1
SH1=2^1=2
SH2=2^2=4
SH3=2^3=8
SH4=2^4=16
SH5=2^5=32
SH6=2^6=64

Consider the quotient states and their numeric representations;

SE0/SH0=1
SE1/SH1=1/2
SE2/SH2=1/2
SE3/SH3=3/2
SE4/SH4=18
SE5/SH5=1080
SE6/SH6=12150

The digits of 4,5,6 all add to 9.

The rest follows with more interesting integers.
But 3/2 is special.
3/2 is the last rational before the large integers start.
Isn't Mandelbrot Set's area almost 3/2?
Isn't 3/2 the all important fifth note in a scale (like C and it's 5th G)?
The 5th in music is very important since the well tempered tuning is based
on the 5th.
When you take 5th of a base note 12 times,
you go through 7 octaves and cover the entire octave, using each note once!


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