Re: The speed of light can not be physically constant to all
- From: The Ghost In The Machine <ewill3@xxxxxxxxxxxxx>
- Date: Wed, 22 Mar 2006 06:31:19 GMT
On Mon, 20 Mar 2006 10:26:28 -0500, Spaceman wrote:
"The Ghost In The Machine" <ewill3@xxxxxxxxxxxxx> wrote in message
news:pan.2006.03.20.05.05.53.882221@xxxxxxxxxxxxxxxx
[quoted text muted]
Miles per second is just a fraction.
(186,000 miles / 1 second) + (93,000 miles / 1 second) = 279000 miles / 1
second
How much distance traveled with the one second 279,000 miles.
You have completely forgotten how to add miles I see?
Fine as far as it goes. One could, for instance, shoot a light beam from
point A and a pellet going 0.5c from point B and calculate closing
velocity as 1.5 c.
However, the pellet will observe the light beam going towards it at
lightspeed.
[quoted text muted]
Actually, Newtonia can explain the "rubber ruler" effect along with the
"taffy ticker". but of course you refuse to think about any such
explanations.
Newtonia can't explain why a 7 TeV proton isn't going many times
lightspeed.
[quoted text muted]
We have been through this too many times. Blowing "more wind" at a
sailboat does not make it travel faster. The sailboat only has a certain
size sail.
Please, Mr Math man calculate the energy in a 1 mile wide by 1/4 mile
high wind with a length of 10 meters. How fast should a 1 ton boat move
with all that energy hitting it at 60 mph?
Did you want to discuss sailboats, spacetime, or particle physics? But OK.
First, there's several issues here; the units are English. Also, a modern
sailboat can generate sideways force since its sail is *curved*, acting in
a manner similar to an airplane's wing. The keel also plays a role in
this sailing.
There's also drag.
But of course you're being slightly silly anyway. A 1 ton, 1 ounce, or 1
pound keelless boat will move at 60 mph -- the same as the windspeed -- if
one neglects friction. Since it's a 1 ton boat one gets a kinetic energy
of approximately 392,000 J. (A keeled boat's speed will be
direction-dependent.)
As for the amount of energy in a rectangular parallelpiped 1 mile by 1/4
mile by 10 meters at 60 mph -- that's a good question, and the answer I
get would be temperature-dependent (ideal-gas law), though the variance
wouldn't be all that much.
Assuming 40 moles per cubic meter, I get 6,500,000 m^3, 2.59 * 10^8 moles,
7.51 * 10^6 kg, 2.70 * 10^9 J -- with only a tiny fraction interceptable
by the sailboat, of course.
--
#191, ewill3@xxxxxxxxxxxxx
It's still legal to go .sigless.
.
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