Re: Physics help
- From: "V - Man" <Vman@xxxxxxxxxxx>
- Date: Sat, 22 Apr 2006 14:55:39 -0400
As John Christiansen noted, the temperature of the water does not change.
Another thing to note is that none of the original chunk of ice melts.
The heat given up by the water is
Q_water = L m_water
where L is the heat of fusion and m is the mass.
The heat absorbed by the ice is
Q_ice = C m_ice (T_f - T_i)
where T_i is the initial temperature, and T_f = 0C is the final
temperature.
Q_water = Q_ice, so, after sorting out the sign convention, solving the
problem becomes simple algebra.
--
"He who only sees business in business is a fool."
So, working out the problem I get Q_water = 80
For Q-ice: C m_ice = 0.50 * 1 (0 - T_i)
After working out the simple algebra, I got -160 C. This doesn't seem
logical. Unless the C m_ice is not correct. Should the m be the final amount
of ice or starting block? If final (2 kg), then the answer is -80 C.
.
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