Re: Electron-orbits, light-wavelength and amplitude
- From: "Radium" <glucegen1@xxxxxxxxxx>
- Date: 4 Jun 2006 18:07:37 -0700
OG wrote:
"Radium" <glucegen1@xxxxxxxxxx> wrote in message
news:1149462944.060524.250720@xxxxxxxxxxxxxxxxxxxxxxxxxxxxxxx
Hi:
Atoms contain electrons. These electrons are in specific orbits. When
an electron move from a higher energy orbit of the atom to a lower
energy orbit of the atom.
http://science.howstuffworks.com/light4.htm quote:
"The photon has a frequency, or color, that exactly matches the
distance the electron falls. "
Does this mean that a fall of greater distance produces a shorter
wavelength? Or will a greater distance fall produce a longer
wavelength? I am confused on this.
the greater the distance the higher the energy of the light (shorter
wavelength)
Also what, at the atomic level determines the amount of photons per
second released [amplitude] when the electron falls from the higher
energy level to the lower energy level?
One photon only per energy level change.
In some cases electrons may fall in two stages, in which case two photons
are produced - each with its own characteristic wavelength.
So what you saying is:
1. A bigger change in energy level will result in a higher-frequency
photon than a smaller change in energy level
and
2. A greater number of changes in energy levels will result in more
photons per second than a lesser number of changes in energy levels
Am I right?
.
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